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Sladkaya [172]
3 years ago
10

Please help me with my homework! Its past due and I am having trouble on it :/

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
5 0

Answer:

the first one is 57

the second one is 60

3rd one is 13

4th one is 9

Step-by-step explanation:

hope this helps :) have a nice day !!

**please let me know if this was wrong**

Nezavi [6.7K]3 years ago
4 0

Answer:

1) In the second step, it was supposed to multiply 9 and 2 and 36 by 3 instead of adding 9 and 3 to each other because multiplication and division comes before adding, according to pemdas.  

2) In the second step, they were supposed to multiply 6 and 4 instead of subtracting 27 and 6 because multiplication comes before subtraction, according to pemdas.

3)

(43 - 20) - 2 · 5

43 - 20 = 23

23 - 2 · 5

2 · 5 = 10

23 - 10 =

13

4) 81 ÷ (13 - 4)

13 - 4 = 9

81 ÷ 9

81 ÷ 9 =

9

5) 7 · 8 - 3 · 6 + 1

7 · 8 = 56

3 · 6 = 18

56 - 18 + 1

56 - 18 = 38

38 + 1 =

39

6)

7)

8)

Step-by-step explanation:

<h3>Section 1: Explain the error in each problem below. </h3>

1) Pemdas says multiplication and division comes before adding, so you must solve the multiplication in the problem first before the addition.  

2) Again, as pemdas says, multiplication comes first before subtraction, so you must solve the multiplication in the problem first before the sutraction.

<h3>Section 2: Simplify the following expressions. </h3>

3) (43 - 20) - 2 · 5

Pemdas says to solve the parenthesis first.

  • 43 - 20 = 23
  • 23 - 2 · 5

Now multiplication comes next (because there's no exponents).

  • 2 · 5 = 10
  • 23 - 10

Now subtraction.

  • 23 - 10 = 13

4) 81 ÷ (13 - 4)

Pemdas says to solve the parenthesis first.

  • 13 - 4 = 9
  • 81 ÷ 9

Now division comes next.

  • 81 ÷ 9 = 9

5) 7 · 8 - 3 · 6 + 1

Pemdas says to solve the multiplication first.

  • 7 · 8 = 56
  • 3 · 6 = 18
  • 56 - 18 + 1

Now subtraction and addition.

  • 56 - 18 = 38
  • 38 + 1 = 39

6)

<h3>Section 3: Insert grouping symbols to make the statements true.  </h3>

7)

8)

P.S. I am updating

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Answer:

Step-by-step explanation:

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z=\frac{12-x-2y}{3}

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find partial derivatives using product rule

f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

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D<0 only for (4,2)

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
3 years ago
Finding Side Lengths
zheka24 [161]

Answer:

  • x = 2.5
  • y = 5

Step-by-step explanation:

As the two figure are the image and pre-image of a dilation.

Considering the left sided triangle is original and right sided triangle ( smaller one) is the image.

As one of the sides of the left triangle (original figure) is 4 in. And the corresponding length of the side on the right triangle (image of the figure) is 2 in.

It means the image of the side (2 in) is obtained when the side (4 in) of the original object is dilated by a scale factor of 1/2. In other words, the side of the image (2 in) is obtained multiplying the side (4 in) of original figure by 1/2. i.e. 4/2 = 2 in

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So, the value of x will be 2.5

Similarly, the original object has one of the sides with length (y + 1 in). As the As the original figure is dilated by a scale factor of 1/2. As the corresponding length of the side of the image triangle is 3 in.

so

y + 1 = 2(3)         ∵ 3 in (image side) is multiplied by 2

y + 1 = 6

y = 6 - 1

y = 5

So, the value of y = 5

Therefore,

  • x = 2.5
  • y = 5
6 0
3 years ago
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