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3 years ago

The final value of a painting after its initial value, m, increases by 2/5

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

3 0

Your answer is D. 2/5m

This expression means 2/5 times the initial value (m).

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Wich expression can be used to find the slope of a line containing the points (-3,2) and (7,-1)

docker41 [41]

$A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\\text{The slope:}\ m=\dfrac{y_2-y_1}{x_2-x_1}$

$\text{We have:}\\(-3;\ 2)\to\ x_1=-3;\ y_1=2\\(7;\ -1)\to x_2=7;\ y_2=-1$

$\text{substitute}\\\\m=\dfrac{-1-2}{7-(-3)}=\dfrac{-3}{10}=-\dfrac{3}{10}$

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3 years ago

Use the formula d = rt to find the distance d a long distance runner can run at a rate of 9 1/2 miles per hour for time t or 1 3

LiRa [457]

D = (9 1/2) (1 3/4) D = 11 7/8 miles

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3 years ago

What is the difference between 100 and 33?

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

100 - 33 = 67

The difference between 100 and 33 is 67.

8 0

2 years ago

Read 2 more answers

Adult entrance fees to amusement parks in the United States are normally distributed with a population standard deviation of 2.5

kondor19780726 [428]

Answer: 1.509

Step-by-step explanation:

The formula of Margin of Error for (n<30):-

$E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n= 22

Level of confidence = 0.99

Significance level : $\alpha=1-0.99=0.01$

Using the t-distribution table ,

Critical value : $t_{n-1, \alpha/2}=t_{21,0.005}= 2.831$

Standard deviation: $\sigma=\text{ 2.5 dollars }$

Then, we have

$E=( 2.831)\dfrac{2.5}{\sqrt{22}}\approx1.509$

Hence, the margin of error for a 99% confidence interval for the population mean =1.509

4 0

3 years ago

Find the distance between two points ( -1,1) and (2,-4)

sladkih [1.3K]

Answer:

The distance between two points ( -1,1) and (2,-4) is:

$d=\sqrt{34}$ or d = 5.8 units.

Step-by-step explanation:

Given the points

(-1, 1)

(2, -4)

Finding the distance between (-1, 1) and (2, -4) using the formula

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

substitute (x₁, y₁) = (-1, 1) and (x₂, y₂) = (2, -4)

$=\sqrt{\left(2-\left(-1\right)\right)^2+\left(-4-1\right)^2}$

$=\sqrt{\left(2+1\right)^2+\left(-4-1\right)^2}$

$=\sqrt{3^2+5^2}$

$=\sqrt{9+25}$

$=\sqrt{34}$ units

$d = 5.8$ units

Therefore, the distance between two points ( -1,1) and (2,-4) is:

$d=\sqrt{34}$ or d = 5.8 units.

3 0

2 years ago