All categories

3 years ago

Can you help me please

Mathematics

1 answer:

sammy [17]3 years ago

3 0

Answer:

196

Step-by-step explanation:

You might be interested in

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

3 years ago

Which number is 300% of the difference between 23 and 27?

Nata [24]

Your answer is 12

The difference 27 – 23 = 4, and 300% of 4 is 3 times 4, or 12.

7 0

3 years ago

Find 3 solutions (ordered pairs) for the equation 3x - 2y = 12

Alex17521 [72]

Answer: (0,−6),(1,−9/2),(2,−3)

I’m pretty sure these are it!

5 0

3 years ago

Determine the intercepts of the line. yy y y -intercept: (\Big( ( left parenthesis ,, , comma )\Big) ) right parenthesis xx x x

BlackZzzverrR [31]

Question:

Give all the x and y intercept of the function

$f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30}$

Answer:

The x intercepts are x = 5 and x = -4

The y intercept is at y = -2

Step-by-step explanation:

Factorizing the numerator of the expression we find the x intercepts as follows;

$f(x) = \frac{3x^2 - 3x-60}{2x^3 + 2x^2-34x+30} =\frac{3(x-5)(x+4)}{2x^3 + 2x^2-34x+30}$

Therefore, the x intercept are

x = 5 and x = -4

To find the y intercept, we put x = 0 to get y = -2

Therefore, the y intercept is at y = -2

Factorizing the denominator we find the values for which the equation is undefined

2·x³ + 2·x² - 34·x + 30 = 2·(x-1)·(x-3)·(x+5) which gives

x = 1, 3 and -5.

4 0

3 years ago

Estaban is making turtle brownies. The recipe calls for 3/4 bags of carmel squares . One bag has 24 caramel squares in it. Estab

motikmotik

He would need 36 carmel squares to make 2 batches

8 0

3 years ago

Can you help me please ​

Can you help me please