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Svetradugi [14.3K]
3 years ago
11

Write the values of the given digits the 2's in 42.256

Mathematics
2 answers:
il63 [147K]3 years ago
6 0

Answer:2000 for the first one 200 for the second

Step-by-step explanation:

defon3 years ago
4 0
42.256

the first 2 is in the ones place

the other 2 is in the tenths place

(tens)(ones).(tenths)(hundreths)
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A circle has a radius of 8.25 feet. To the nearest square foot, what is the area of the circle?
Natali [406]

Answer: 214 ft^2

Step-by-step explanation:

A=πr^2

3.14(8.25)^2

3.14(68.0625)

213.71625

rounded to the nearest square foot: 214

7 0
3 years ago
Please help me please
Alchen [17]
The answer to the question is c
5 0
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Kris spent for 4.37 hours per day for 3 days practicing soccer this week. Amelia spent 6.39 hours per day for 4 days practicing
postnew [5]
Kris:
4.37 hours per day for 3 days.
To find the total practice time, multiply the practice time per day by the number of days.
4.37 • 3 = 13.11
This means Kris practiced for 13.11 hours.

Amelia:
6.39 hours per day for 4 days.
To find the total practice time, multiply the practice time per day by the number of days.
6.39 • 4 = 25.56
This means Amelia practiced for 25.56 hours.

To find the difference, just subtract Kris's practice time from Amelia's practice time.
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This means Amelia practiced for 12.45 more hours than Kris.
6 0
3 years ago
Read 2 more answers
Which value of x makes the open sentence true? 10 +m2x< 15x-20? 0, 1, 2,3
Zielflug [23.3K]

x=3 if the m was a typo, idk what that means

3 0
3 years ago
A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 20 ft from the path and is kept f
krek1111 [17]

Answer:

0.128rad/sec

Step-by-step explanation:

Let x represent the between the man and the point on the path

θ = the angle

dx/dt = 4 ft/s

dθ/dt = rate is the searchlight rotating when the man is 15 ft from the point on the path closest to the searchlight

tan θ = x/20 ft

Cross Multiply

20tan θ = x

dx/dt = 20sec² θ dθ/dt

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dθ/dt= 1/20 × cos² θ × 4

dθ/dt = 1/5 × cos² θ

Note : cos θ = 4/5

dθ/dt = 1/5 × (4/5)²

dθ/dt = 16/125

dθ/dt = 0.128rad/sec

6 0
3 years ago
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