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Sphinxa [80]
3 years ago
13

Hey! I am stuck on this question anyone mind helping me? and tysm for the people who helped me! <3 have a nice day!

Mathematics
1 answer:
Andrej [43]3 years ago
4 0

Answer: 166 2/3m

Step-by-step explanation:

Area of a rectangle = length times width

Length: 16 2/3

To find the width, multiply it by 3/5.

w = 16 2/3 ·  3/5

w = 10

Then, multiply the length by the width.

a = l · w

a = 16 2/3 · 10

a = 166 2/3m

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44 is 25% of what <br> pls help they gave me these without teaching them
Anna71 [15]

Answer:

176

Step-by-step explanation:

In order to find these kinds of problems, you need to divide the given number by the percentage in its decimal form.

25% = 0.25

44/0.25 = 176

To check your work, simply take the answer and multiply it with the percentage.

176*0.25 = 44

7 0
3 years ago
A survey of the whole United States shows that 75% of 6th grade students like sports that involve running, that 60% of boys like
slamgirl [31]

Answer: 75% of 6th Grade Students

Step-by-step explanation:

This sample makes the most sense because it is a majority of everyone, not just a majority of certain people. Also, Mountain School would get fewer complaints from other people if they went with a majority of 75%. Finally, running sports usually cost less then other sports.

3 0
2 years ago
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
Identify the expressions for which limits exist.
alexdok [17]

Answer:

..............

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Question 15 and Question 18 antidifferentiate?
soldi70 [24.7K]

Answer:

#15: 1/5 (x^2 - x - 3)^5

#18: 5 (3x^2 - 6x + 1)^5


Step-by-step explanation:

#15

(2x-1)(x^2-x+3)^4

Chain Rule!!!

g'(x)f'(g(x)) = d/dx(f(g(x)) = (f ⚬ g)'(x)

f'(x) = x^4

g(x) = x^2 - x - 3

g'(x) = 2x - 1

So we only have to integrate x^4 gives 1/5 x^5

f(x) = 1/5 x^5

f(g(x)) = (f ⚬ g)(x) = 1/5 (x^2 - x - 3)^5


#18

150(x-1)(3x^2-6x+1)^4

Chain rule again!! In disguise.

f'(x) = x^4

f(x) = 1/5 x^5

g(x) = 3x^2-6x+1

g'(x) = 6x - 6 = 6(x-1)

150(x-1) = 25 g'(x)

25 g'(x)f'(g(x)) = 25 (f ⚬ g)(x) = 5(3x^2-6x+1)^5


3 0
3 years ago
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