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lys-0071 [83]
3 years ago
6

The scale on a map shows that 2 inches represents 15 miles. Which proportion can be used to find the actual distance, x, represe

nted by 30 inches on the map? StartFraction 2 over 15 EndFraction = StartFraction 30 over x EndFraction StartFraction 2 over 15 EndFraction = StartFraction x over 30 EndFraction StartFraction 15 over 30 EndFraction = StartFraction 2 over x EndFraction StartFraction 15 over 30 EndFraction = StartFraction x over 2 EndFraction
Mathematics
2 answers:
sertanlavr [38]3 years ago
5 0

Answer:

b

Step-by-step explanation:

aleksklad [387]3 years ago
4 0

Answer:

its b  hi how was yalls day

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What is the x-intercept of the graph that is shown below?
Hatshy [7]

Answer:

(-2, 0)

Step-by-step explanation:

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Help me with this question
Llana [10]

The answer is B

(3^4*abc^-7)^6=(3^4*6)(a^6)(b^6)(c^6*-7)=(3^24*a^6*b^6)/(b^42)

6 0
3 years ago
An object is placed 21 cm from a concave lens of focal length 25 cm. what is the magnification?
wariber [46]

The magnification is 0.54

Given,

The distance between object and concave lens, u = -21 cm

Focal length of the concave lens, f = -25 cm

Let m be the magnification.

m = v/u

Here v is the position of image.

We have to find v first.

By using lens equation we can determine v.

That is,

1/f = 1/v – 1/u

So,

- (1/25) = 1/v – (-1/21)

- (1/25) = 1/v + 1/21

1/v = - (1/25) – 1/21

1/v = (-25 – 21) / (21 x 25)

1/v = - (46/525)

Therefore v = - (525/46)

   v = -11.41 cm

Now we have to find magnification, m.

m = v/u

   = (-11.41) / (-21)

   = 0.54

Here magnification is 0.54

Learn more about concave lens here: brainly.com/question/12944945

#SPJ4

6 0
2 years ago
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