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3 years ago

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Clare is paid $90 for 18,000 seconds of work. At this rate, how many seconds does it take for her to earn 25 cents? It would tak

e Clare seconds to earn a quarter.

1 answer:

Anastaziya [24]3 years ago

5 0

Answer: 50 seconds

Step-by-step explanation:

From the question, we are informed that Clare is paid $90 for 18,000 seconds of work. This means that for Clare to get $1, she'll work for (18000/90) = 200 seconds. From the calculation $1 = 200 seconds

We should note that 100 cents = $1, therefore 25 cents = 25/100 = $0.25.

The seconds that it will take for her to earn 25 cents will be:

= 200 × 0.25

= 50 seconds

Therefore, it'll take 50 seconds for her to earn 25 cent.

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The experimental units in this experiment are the 10 plants in group 2.

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Then, the answer is D, because it refers to the experimental unit corresponding to this experiment.

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2 years ago

What is the measure of the angle ?

Roman55 [17]

Answer:

Answer → C) 121°

Step-by-step explanation:

» Let the wanted angle be x

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2 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

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Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y= x/3−1

Alex_Xolod [135]

Perpendicular lines have slopes that are opposite and reciprocal. Therefore, the line we are looking for has a -3 slope.
y= -3x+b

Now, we can substitute in the point given to find the intercept.
2= -3(4)+b
2= -12+b
b=14

Finally, put in everything we've found to finish the equation.
y= -3x+14

6 0

3 years ago