Ask question

Ask question

All categories

3 years ago

8

Clare is paid $90 for 18,000 seconds of work. At this rate, how many seconds does it take for her to earn 25 cents? It would tak

e Clare seconds to earn a quarter.

1 answer:

Anastaziya [24]3 years ago

5 0

Answer: 50 seconds

Step-by-step explanation:

From the question, we are informed that Clare is paid $90 for 18,000 seconds of work. This means that for Clare to get $1, she'll work for (18000/90) = 200 seconds. From the calculation $1 = 200 seconds

We should note that 100 cents = $1, therefore 25 cents = 25/100 = $0.25.

The seconds that it will take for her to earn 25 cents will be:

= 200 × 0.25

= 50 seconds

Therefore, it'll take 50 seconds for her to earn 25 cent.

You might be interested in

Find the slope <br> The slope is —-??,

Darya [45]

Answer:

The slope is undefined.

Step-by-step explanation:

All vertical segments are undefined. All horizontal segments are 0.

7 0

3 years ago

Read 2 more answers

A walking trail is 3.8 miles long. If Gertrude walked the length of the 1 walking trail 13 times, how many miles did Gertrude wa

MAVERICK [17]

Answer:

hehduhewduehusdu

Step-by-step explanation:

pay back

5 0

3 years ago

Anyone knows the answer?

antiseptic1488 [7]

Sorry no but you can search up the question on google and maybe try that

8 0

3 years ago

Simplify. What is your answer 8x + 9d + 3x -5d

BlackZzzverrR [31]

Answer:

11x + 4d

Step-by-step explanation:

8x + 9d + 3x -5d

To simplify this we have to group them by their like terms i.e.

= 8x + 3x + 9d - 5d

= 11x + 4d

Mark brainliest

7 0

3 years ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago