Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of

Question

3 years ago

8

the measurement, to the nearest tenth of a percent?

2 answers:

algol13 · Answer 1 · 2022-10-01T14:26:17+03:00

algol133 years ago

8 0

Answer:

3.9%

Step-by-step explanation:

Percentage error

$= \frac{7.7 - 7.4}{7.7} \times 100 \\ \\ = \frac{0.3}{7.7} \times 100 \\ \\ = \frac{300}{77} \\ \\ = 3.8961039 \\ \\ = 3.9 \%$

kirill [66] · Answer 2 · 2022-10-01T15:45:42+03:00

8 0

I think it’s 3.8% i’m not sure tho