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2 years ago

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Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of

the measurement, to the nearest tenth of a percent?

2 answers:

algol132 years ago

8 0

Answer:

3.9%

Step-by-step explanation:

Percentage error

$= \frac{7.7 - 7.4}{7.7} \times 100 \\ \\ = \frac{0.3}{7.7} \times 100 \\ \\ = \frac{300}{77} \\ \\ = 3.8961039 \\ \\ = 3.9 \%$

kirill [66]2 years ago

8 0

I think it’s 3.8% i’m not sure tho

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Solve the following: - 3 raised to 1 by 5 the whole raised to 4 (3^1/5)^4

Diano4ka-milaya [45]

Answer:

8.30256

Step-by-step explanation:

Step 1: Write out expression

$((-3)^{\frac{1}{5} })^{4(3^{\frac{1}{5} })^4$

Step 2: Use BPEMDAS to evaluate

$(-1.24573)^{4(3^{\frac{1}{5} })^4$

$(-1.24573)^{4(1.24573)^4$

$(-1.24573)^{4(2.40822)$

$(-1.24573)^{9.6329}$

= 8.30256

And we have our answer!

8 0

3 years ago

I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

<u>Given</u>:

$m\angle Z = 138^{\circ}$

<em><u>Note the following:</u></em>

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

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The property shown is commutative multiplication. This property says that the product of two factors is not affected by the order in which they're multiplied. In this case, the product remains the same i.e., 2*8*5 = 80 while 2*5*8 <em>also </em>equals 80.

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borishaifa [10]

If you put 0 in the place of x or y, which every one you choose, it will cancel it or and you can just divide the number next to it by the answer (-20, 20). Take it one step at a time, don't try to do both at the same time.

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Step-by-step explanation:

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