28 - 2.2x = 11.6x - 54.8
28 + 54.8 = 11.6x + 2.2x
82.8 = 13.8x
82.8 / 13.8 = x
6 = x
or x = 6
Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
"If you subtract 17 from my number and multiply the difference by negative 4, the result is negative 92.
n= number
(n-17)*(-4) = -92
distribute
-4 *n - 17*(-4) = -92
-4n +68 = -92
subtract 68 from each side
-4n +68-68 = -92 -68
-4n = -160
divide each side by -4
-4n/-4 = -160/-4
n = 40
Julio's number is 40
Answer: B) False
A counter-example would be the cubic polynomial y = x^3 which doesn't have a max or a min. The graph stretches forever in both directions (up and down) indicating that the range is the set of all real numbers.
