PLEASE HELPPPPPPPPPP

Mathematics

1 answer:

Sauron [17]3 years ago

3 0

Answer:

167/346 or 0.483

Step-by-step explanation:

From the question given above, the following data were obtained:

Number of Tails (T) = 167

Number of Heads (H) = 179

Probability of tail, P(T) =?

Next, we shall determine total outcome. This can be obtained as follow:

Number of Tails (T) = 167

Number of Heads (H) = 179

Total outcome (S) =?

S = T + H

S = 167 + 179

Total outcome (S) = 346

Finally, we shall determine the probability of tails. This can be obtained as follow:

Number of Tails (T) = 167

Total outcome (S) = 346

Probability of tail, P(T) =?

P(T) = T / S

P(T) = 167 / 346

P(T) = 0.483

Thus, the probability of tails is 167/346 or 0.483

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The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv

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The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

The mass of the particles moving in river is proportional to the sixth power of 2, or $2^6 = 64$ miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship $x * 2^6 = k$ , for some constant k.

For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

So, the key here is proportional. We can set up two proportions and cross multiply.

$\dfrac{x}{2^6} = \dfrac{15x}{y^6} \\ (x)(y^6)=(2^6)(15x)$

Cancelling our x's (because we don't need to solve for them), we have

$y^6 = 15(2^6) = 15(64)=960$

To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

$\sqrt[6]{y^6} = \sqrt[6]{960}$

Using a calculator, we see that $\sqrt[6]{960} = 3.14 \ miles \ per \ hour$ .