Answer:
she needs to sell at least 44 cookies to make a $0.10 profit
Step-by-step explanation:
to find the answer all you have to do is divide 15.30 by 0.35
Answer:
1) No
2) No
3) Yes
4)Yes
5) No
6) No
Step-by-step explanation:
In a function, no domains (x-coordinates) are repeated. Only graphs 3 and 4 meet this requirement.
Hope it helps!
B (2<3)and C (4+3=7) maybe
Answer: 
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Explanation:
r = number of red pens
4r = cost of buying r red pens
example: if r = 10, then 4r = 4*10 = 40 is the total cost of buying 10 red pens
If John buys r red pens, then he must buy 20-r black pens so that r and 20-r add to 20.
John buys 20-r black pens, and at $5 each, so it will cost 5(20-r) dollars for just the black pens alone.
In total, John spends 4r + 5(20-r) dollars for all the pens (red & black)
We want $92 be the most he spends. This is the ceiling or highest value possible.
Therefore,

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Extra info:
If you want to solve for r, then

distribute

add r to both sides

subtract 92 from both sides


So John must buy at least 8 red pens. The most he can buy is 20 red pens since he wants 20 pens total.
Step-by-step explanation:
Given f(x) = 5x - 7 and g(x) = x² - 3, find f(f(2))