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Marysya12 [62]
2 years ago
13

Can someone help me with this and show me the steps if you don't mind

Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
8 0

Answer:

(x+8)(x+5)

Step-by-step explanation:

Since we know x2 is equivalent to x times x we can automatically start by filling in the first two spaces with x. Then since we know that we're going to need two numbers that equal forty since it's part of the equation we can get two number that will also add up to 13x which is 8 and 5. We then get (x+8)(x+5). (Sorry lol this question is kind hard to explain over the computer.)

earnstyle [38]2 years ago
8 0

Answer:

it's A

Step-by-step explanation:

5x8=40 and 5+8=13

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graph the number that represents the situation on a number line. please help with this question i will mark you brainliest!
Alja [10]

Answer:

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5 0
2 years ago
NO LINKS OR FILES!
Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

7 0
2 years ago
Least common denumertor of 11/3 9/10
Alisiya [41]
30 since that’s the lowest number both 3 and 10 can fit in
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2 years ago
Li’s recipe uses 3 2/3 cups of flour. He plans to make 4 batches. How much flour will li need. I need help on finding out what t
pishuonlain [190]

Answer:

14 and 2/3rd cups of flour for 4 batches

Step-by-step explanation:

3 0
3 years ago
Flaws in a carpet tend to occur randomly and independently at a rate of one every 270 square feet. What is the probability that
Alisiya [41]

Answer:

The probability that it contains no flaws=0.585

Step-by-step explanation:

Flaws in a carpet tend to occur randomly and independently at a rate of one every 270 square feet.

One = 270 ft²

8*14= 112 ft²

Probability of containing flaws

So if 270 ft² = 1

112 ft² = 112/270

112ft² = 0.415

The probability that it contains no flaws= 1- probability that it contains

The probability that it contains no flaws= 1-0.415

The probability that it contains no flaws=0.585

6 0
2 years ago
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