Please answer this question

These data provides the responses of 10 students in class A and in class B who were asked how many hours they slept lastThese da

dmitriy555 [2]

Answer:

Answer C

Explanation:

Class A Median: 4, 5, 6, 6, 7, 7, 7, 7, 8, 8

The Median of Class A is 7.

Class B Median: 5, 6, 6, 6, 7, 7, 7, 8, 8, 9

The Median of Class B is 7.

Class A Mean: 4 + 5 + 6 + 6 + 7 + 7 + 7 + 7 + 8 + 8 = 65

To find the mean, you add all of the numbers together, and divide the total by the amount of numbers. (There are ten numbers in the equation, so we divide 65 by 10.)

65/10 = 6.5, This means that the mean of Class A is 6.5

Class B Mean: 5 + 6 + 6 + 6 + 7 + 7 + 7 + 8 + 8 + 9 = 69

Do the same thing as last time, divide 69 by 10. (6.9)

The mean of class B is 6.9

Answer A and B are both incorrect, because the medians for both classes were the same. Answer C is correct, because the mean of class B was 6.9 and the mean of Class A was 6.5

Answer D is also incorrect, 6.9 is 0.4 greater than 6.5

Solved by Inspire! (14 years old)

3 0

2 years ago

Which of the following is an example of a trade journal?

Genrish500 [490]

Answer:

since d is incorrect as you said the answer is b then Sports Business Weekly

4 0

2 years ago

Read 2 more answers

How exactly do you find the circumference by using C++ Programming? I really need a specific answer.

adelina 88 [10]

Answer:

C++ Program to Find Area and Circumference of a Circle

Area of Circle = PI X Radius X Radius. Where, Where PI is a constant which is equal to 22/7 or 3.141(approx)

Circumference or Circle = 2 X PI X Radius.

Circumference or Circle = PI X Diameter.

Explanation:

3 0

2 years ago

(20 points). Some matrixes have very special patterns, for example, in the following matrix, the numbers in the first row are eq

Nostrana [21]

Answer:

#include <iostream>

using namespace std;

void matrix(){

int row = 5, col = 6;

int myarr[row][col];

for (int i = 0; i < 5; i++){

for (int x = 0; x < 6; x++){

if (i == 0){

myarr[i][x] = (x+1)*(x+1);

}else if ( x == 0){

myarr[i][x] = (i+1)*(i+1)*(i+1);

} else if ( i == x){

myarr[i][x] = (i+1);

} else{

myarr[i][x] = myarr[i-1][x] + myarr[i][x-1];

}

for (int i = 0; i < 5; i++){

for (int x = 0; x < 6; x++){

cout<< myarr[i][x] << " ";

}

cout<< "\n";

}

int main(){

matrix();

}

Explanation:

The C++ source code defines a two-dimensional array that has a fixed row and column length. The array is a local variable of the function "matrix" and the void function is called in the main program to output the items of the array.

3 0

1 year ago

Suppose an IP packet is fragmented into 10 fragments, each with a 1% (independent) probability of loss. To a reasonable approxim

Marysya12 [62]

Answer:

a. 0.01

b. 0.001

c. The identification field of the packet fragment can be used to uniquely identify and collate the fragments lost in transmission.

Explanation:

The probability of losing a packet is 10% or 0.1, so the probability of losing the packet twice during transmission;

= 0.1 x 0.1 = 0.01

When any fragments have been part of the transmission, the probability of the packet is dependent on the fragments;

= 0.01 x 0.1 = 0.001

The identification field is a unique 16-bit value assigned to an IPv4 packet, when a packet is fragmented for transmission, its field is used to collate the unique fragments in the packet.

6 0

2 years ago

Please answer this question​

Please answer this question