Answer:
a. a syntax error
Explanation:
When the same variable name is repeated in the parameter set and the method body, it will result in a syntax error. This is because the variable in the parameter has a local scope within the method body. Now if we declare another variable with the same name in the method body, it will result in redefinition of the variable and violate the uniqueness principle of variable names in the method code. This will give rise to syntax error.
Answer:
#include<iostream>//library inclusion
using namespace std;
int main()
{
int userInput;
do//start of do while loop
{
cout << "Enter a number less than a 100" << endl;
cin >> userInput;
if (userInput < 100) //condition
{
cout << "YOu entered less than a hundred: " << userInput << endl;
}
else
{
cout << "your number is greater than 100" << endl;
}
} while (userInput > 100);//condition for do while
return 0;//termination of int main
}
Explanation:
The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.
The answer is B because it is short and simple and gets you to the point
Or by searching up the desired content and or information on a search engine. I believe.
Answer:
Im not sure why but maybe you can find a way to contact the people who own it and see if they know because that hasn't happened to me. How many questions have you asked
Explanation:
