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nexus9112 [7]
3 years ago
9

Write the number 16, 107, 320 in expanded form.

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

398383i4irujidifififif

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If someone helps me with dis ill give u brainliest​
jolli1 [7]

Answer:

4 different answers

Step-by-step explanation:

1.

[(24/3) + (5*2^2)] = 28

2.

[(3 + 5) * 2^2 )]/24 = 32/24 = 4/3

3.

[(24/3 + 5)*2^2] = 52

4.

[(3 + 5*2^2)/24] = 23/24

5 0
3 years ago
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If two halves of two whole 1/2 are added to two whole 1/2 the result is
jekas [21]
1 is the answer hope this helps
8 0
3 years ago
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100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
8 x 10^-3 is how many times as great as 4 x 10^-6
mamaluj [8]

For this case we can rewrite the expressions as:

3 * 10 ^ {- 3} = 0.003

That is, we run the decimal three times to the left.

4 * 10 ^ {- 6} = 0.000004

That is, we run the decimal six times to the left.

So:

0.003-0.000004 = 0.002996

So, we have that 3 * 10 ^ {- 3}is 0.002996 times bigger than 4 * 10 ^ {- 6}

Answer:

3 * 10 ^ {- 3}is 0.002996 times bigger than 4 * 10 ^ {- 6}

7 0
3 years ago
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If you weighed 92 pounds on Earth, you would weigh 97.8 pounds on Saturn. write the weight on Saturn as a mixed number in simple
SIZIF [17.4K]

Answer:

97 8/10

Explanation:

If you weighed 97.8 pounds on saturn as a decimal, you would take the whole number 97. Now you're left with the ".8" = ".80" this decimal would be 8/10. Now you put them together to create 97 and 8/10.

3 0
3 years ago
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