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Nat2105 [25]
2 years ago
15

I"LL MAKE YOU BRAINLIEST IF YOU ANSWER

Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0

Answer:

30 minutes per miles

Step-by-step explanation:

Set up proportion and cross multiply to solve:

15 min/0.5 miles = x/1 mile

x = 30 min

I hope this helps!

Ivan2 years ago
4 0

Answer:

30 miles per minute

Step-by-step explanation:

The ratios 30/1 is equivalent to 15/0.5.

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Find the Area of the circle. Round your answer to the nearest hundredth. <br> Diameter is 3in.
Sidana [21]

Answer:

A = 7.07

Step-by-step explanation:

A = pi 1.5^2

A = pi 2.25

A = 7.07

5 0
3 years ago
What are the coordinates of this point help plssssssssssssssss<br>​
meriva

Answer:

(-2, -4)

Step-by-step explanation:

Use the (x,y) thing:

x = -2

y = -4

therefore, (-2, -4)

6 0
2 years ago
Card
Burka [1]

Answer:

19,27 cm^2

Step-by-step explanation:

area of triangle = (6 x 3)/ 2 = 9 cm^2

circle area : 3^2 x 3,14 = 28,27 cm^2

area of shaped region = 28,27 - 9 = 19,27 cm^2

6 0
3 years ago
What is a counterexample of the statement “all square roots are irrational”
skad [1K]

Rather than trying to guess and check, we can actually construct a counterexample to the statement.

So, what is an irrational number? The prefix "ir" means not, so we can say that an irrational number is something that's not a rational number, right? Since we know a rational number is a ratio between two integers, we can conclude an irrational number is a number that's not a ratio of two integers. So, an easy way to show that not all square roots are irrational would be to square a rational number then take the square root of it. Let's use three halves for our example:

\sqrt{(\frac{3}{2})^2}=\\\sqrt{\frac{9}{4}}=\\\frac{3}{2}

So clearly 9/4 is a counterexample to the statement. We can also say something stronger: All squared rational numbers are not irrational number when rooted. How would we prove this? Well, let \frac{a}{b} be a rational number. That would mean, \frac{a^2}{b^2}, would be a/b squared. Taking the square root of it yields:

\sqrt{\frac{a^2}{b^2}}}=\\ \frac{\sqrt{a^2}}{\sqrt{b^2}}=\\ \frac{a}{b}

So our stronger statement is proven, and we know that the original claim is decisively false.

3 0
3 years ago
Please help! Confused and my teacher sucks lol
iren [92.7K]
(4,3) should be the coordinates for point V
7 0
4 years ago
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