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2 years ago

I"LL MAKE YOU BRAINLIEST IF YOU ANSWER

Mathematics

2 answers:

Rom4ik [11]2 years ago

6 0

Answer:

30 minutes per miles

Step-by-step explanation:

Set up proportion and cross multiply to solve:

15 min/0.5 miles = x/1 mile

x = 30 min

I hope this helps!

Ivan2 years ago

4 0

Answer:

30 miles per minute

Step-by-step explanation:

The ratios 30/1 is equivalent to 15/0.5.

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lara31 [8.8K]

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2 years ago

A gallon of milk costs $3 nowIf the price is increasing 10% per year, how long before a gallon of milk costs $10 a gallon? Round

r-ruslan [8.4K]

Answer:

The answer is 33 years.

Step-by-step explanation:

10% of 3 is .3

Just move the decimal to the left.

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3 years ago

A shooting star forms a right triangle with the Earth and the Sun, as shown below:

frez [133]

The positions of the sun, earth and shooting star form a right angled triangle, where distance between earth and sun is 'y', and the angle 'x°' is given

Now, in a right angled triangle using trigonometry, we can determine a side of the triangle is one of the sides and one of the angles is known

Here, if we use cos x = $\frac{Base}{Hypotenuse}$ we can determine the distance between the shooting star and the sun. This can be done because we know that the base is 'y', the angle is x° and the hypotenuse represents the distance between the sun and the shooting star

Note: cos values for each x are definite.

3 0

3 years ago

15 cm 15 cm 16 cm 20 cm 57 cm What is the perimeter of the polygon?

Natasha2012 [34]

Answer:

Step-by-step explanation:

15 x 16=240 x 2= 480

57 x 20= 1140

1140 + 480 = 1620

6 0

2 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

1 year ago