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devlian [24]
3 years ago
11

Can anyone help me with my work? Ill give credit to those who do. I'll just put my z00m contact below and add me so we can work

on it, thanks!
Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:

I mean i got class in 2 minutes bUT ILL TAKE THE POINTS THO

Step-by-step explanation:

Rashid [163]3 years ago
8 0
I mean like I’m already in class lol
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You want to solve 11% of what number is 22. Explain how you could solve that but using a proportion
slega [8]
11%=11/100

11/100=22/x


we have to solve for x now

11x=2200 divide by 11 both side

x=200

that the answer

8 0
2 years ago
-y varies inversely with x. When y = 9.6, x = 12. What is the value of k, the constant of inverse variation?
alisha [4.7K]

Question 1:

For this case we have an equation of the form:

y = \frac {k} {x}

Where,

  • <em>k: inverse variation constant. </em>

Then, substituting values we have:

y =\frac {k} {x}

From here, we clear the value of k.

We have then:

k = 9.6 * 12\\k = 115.2

Answer:

the constant of inverse variation is:

k = 115.2

Question 2:

For this case we have:

y = \frac {k} {x}

Where,

  • <em>k: constant of variation. </em>

Then, substituting the value of the constant we have:

y =\frac {5.6} {x}

We now substitute the value of x:

y = \frac {5.6} {4}\\y = 1.4

Answer:

 the value of y when x = 4 is: y = 1.4

6 0
3 years ago
Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal
a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{1}{y + 49} + \dfrac{1}{y} = \dfrac{1}{49}

Or, \dfrac{y + 49 + y}{y^{2} + 49 y } = \dfrac{1}{49}

Or, 2 y + 49 = \dfrac{y^{2}+49y }{19}

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = \frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or,  y = \frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}

Or, y = \frac{- 1 \pm \sqrt{121+3724}}{2}

or, y = \frac{- 1 \pm \sqrt{3845}}{2}

or, y = \frac{- 1 \pm 62.008}{2}

∴   y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0
2 years ago
Use the pythagorean theorem to prove that this point lies on the unit circle. Find csc(0) where 0=-120.
exis [7]

By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.

<h3>How to prove this point lies on the unit circle?</h3>

In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:

Reference angle = 180 - θ

Reference angle = 180 - 120

Reference angle = 60°.

For the coordinates, we have:

sin(-120) = -sin(60) = -1/2.

cos(-120) = -cos(60) = -√3/2.

By applying Pythagorean theorem, we have:

z² = x² + y²

z = √((-1/2)² + (-√3/2)²)

z = √(1/4 + 3/4)

z = √1

z = 1.

Read more on unit circle here: brainly.com/question/9797740

#SPJ1

4 0
2 years ago
Is the ordered pair (0.5, 8.5) a solution to the following equations?
diamong [38]

Answer:

It's yes

Step-by-step explanation:

6 0
3 years ago
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