Answer:
Step-by-step explanation:
y∞x
then
y=kx (with k as constant)
y=5 when x=8
⇒Putting this in the first equation
⇒5=k×8
⇒k=5/8
Now
y=? when x=64
Putting x=64 in the first equation
y=kx
⇒y=(5/8)×64
We get
y=40
Hope u understand
Answer:
Step-by-step explanation:
![[(6^{2}+8^{2})^{\frac{1}{2}}]^{3} = [(36+64)^{\frac{1}{2}}]^{3}\\\\= [(100)^{\frac{1}{2}}]^{3}\\\\= 10^{3}\\\\= 1000](https://tex.z-dn.net/?f=%5B%286%5E%7B2%7D%2B8%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%5E%7B3%7D%20%3D%20%5B%2836%2B64%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%5E%7B3%7D%5C%5C%5C%5C%3D%20%5B%28100%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5D%5E%7B3%7D%5C%5C%5C%5C%3D%2010%5E%7B3%7D%5C%5C%5C%5C%3D%201000)
The first derivative is 5
Answer:
PR5T represents <em>6754.</em>
P = 6
R = 7
T = 4
Y = 5
Step-by-step explanation:
Let us try to understand the subtraction starting from the unit's digit.
P R 5 T
- 4 7 Y 6
-----------------
1 9 9 8
To get 8, 6 should be subtracted from 14
14 - 6 = 8
So, T should be equal unit digit of 14 <em>i.e.</em> T = 4 and 1 should be carried over from the ten's digit of PR5T.
Now, let us move to ten's digit:
P R 5 4
- 4 7 Y 6
-----------------
1 9 9 8
To get 9, 6 should be subtracted from 15. But 1 is already carried to unit's place So, we have actually 14 here
14 - Y = 9
So, Y = 5
Moving to hundred's place:
R - carry - 7 = 9
Carry is 1, so R = unit's place of 9 + 8 i.e. R = 7
Moving to thousand's place:
P - carry - 4 = 1
Here carry is 1
So, P = 1 + 4 + 1 = 6
So, the number PR5T is <em>6754.</em>
5x+12=37
X=5
Hope u do well on the test