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2 years ago

12

X+ 4y = 3

2 answers:

snow_lady [41]2 years ago

8 0

Answer:

The answer is d

Step-by-step explanation:

Whitepunk [10]2 years ago

5 0

D. (-1,1) when plugged in for variables they are true.

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Which property can be justified using the ratios in triangle XYZ ?

Alenkasestr [34]

The correct answer is B.

Determine and recall first the trigonometric functions:

Sin A = Opposite/Hypotenuse
Cos A = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent

If for example we try to take an angle, for example the Y, then Y is opposite Y. The Hypotenuse will be the longer side which is going to denoted by X and the next side will be Adjacent which will be denoted by Z.

Use this test to answer:

Sin Y = Y/X

where:

Y = opposite
X = hypotenuse

Cos (90 - y) = cos (90 - 50) = cos 40

where Z = 40
we look for cos Z = Y/X

Therefore,

Sin Y = Cos (90 - Y)

6 0

2 years ago

Read 2 more answers

To eliminate the y terms, you can multiply the first equation by 5 and the second equation by what number?

gladu [14]

Step-by-step explanation:

the second equation should be multiplied by 9

6 0

2 years ago

Bob recorded the number of hours each person watched TV in a week. He then organized the information in a frequency table.

seraphim [82]

Answer:

yque ha haceqr ailluey

Step-by-step explanation:

6 0

2 years ago

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

7 0

3 years ago

Subjects for the next presidential election poll are contacted using telephone numbers in which the last four digits are randoml

vovikov84 [41]

Answer: 0.3439

Step-by-step explanation:

Given :The last four digits for telephone numbers are randomly selected (with replacement).

Here , each position can be occupied with any of the digit independently .

Total digits = 10

Total digits other than 0 = 9

For each digits , the probability that it is not 0 = $\dfrac{9}{10}=0.9$

If we select 4 digits , The probability of getting no 0 = $(0.9)^4 =0.6561$

(By multiplication rule of independent events)

Now , the probability that for one such phone number, the last four digits include at least one 0. = 1- P(none of them is 0)

=1- 0.6561=0.3439

Hence, the probability that for one such phone number, the last four digits include at least one 0. is 0.3439 .

4 0

2 years ago