Answer:
C. Triangle BAC is congruent to triangle FDE by AAS
Step-by-step explanation:
BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.
The only viable answer choice is C.
No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ = 
L.H.S = sin θ cos θ
so, sin θ cos θ ≠
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
Answer:
48.06 to the nearest hundredth.
Step-by-step explanation:
f(x) = -16x^2 + 2x + 48
To find the maximum height we convert to vertex form:
= -16(x^2 + 1/8x) + 48
= -16[x + 1/16)^2 - 1/256] + 48
= -16(x + 1.16)^2 + 16/256 + 48
= 48.0625.
Answer:
-18.
Step-by-step explanation:
They're both negative numbers being added to each other, so you'd add 6 and 12 (which is 18) and then put a negative sign before the 18. Therefore, your answer is -18.
I hope this helps, have a nice day.
Answer:
(-2,-5), (0,-4), (3,5) (1,1)
Solution:
Only (0,-4) is on the line
(-2,-5), (1,1), and (3,5) is in the orange
(5,5) Isn't right because it's not on the line nor in the orange
