Answer:
12
Step-by-step explanation:
This is a joint variation problem:
z varies directly as x and y
Interpreting this;
z ∝ xy
Therefore;
z = kxy
z = 6, x = 2, y = 6
Now find k,
6 = 2 x 6 x k
6 = 12k
k = 
To find the value of z;
x = 3, y = 8
z = x 3 x 8 = 12
Remember,
To subtract 2/3-1/2 you have to make them equivalent
2/3×2-1/2×3 = 4/6 - 3/6=
1/6
Answer:
Step-by-step explanation:
Answer:
By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.
1/a - 1/b = 1/c : add 1/b to both sides
1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator
1/a = (1/b)(c/c) + (1/c)(b/b) : simplify
1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match
1/a = (c + b)/bc : multiply both sides by a
1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]
1[bc/(b + c)] = a
a = bc/(b + c)
This will not work if c = -b, because then you would be dividing by zero.
Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6
a = bc/(b + c) => 2 = (3 x 6)/(3 + 6) => 2 = 18/9 => 2 = 2.
Step-by-step explanation:
Answer:
Step-by-step explanation:
(2^6)^-5 is the expression that should be multiplied
