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Evgen [1.6K]
3 years ago
10

1/3(-15 divide 1/2) 1/4 what does it equal

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

-2.5 or - 2 1/2

Step-by-step explanation:

Writing out the expression Mathematically ;

1/3(-15÷1/2)1/4

Using PEMDAS :

Solving the bracket first

(-15 ÷ 1/2) = (-15 * 2/1) = - 30

We have :

1/3(-30)1/4 = - 10 * 1/4 = - 10 / 4 = - 2.5

-2.5 = - 2 1/2

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That helps you to conclude:

a) The graph of f(x) has a vertex on (-4, -6)

b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.

c) The graph of f(x) opens downward

d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)

Answer: the graph of f(x) is horizontally stretched.

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3 years ago
For a test of population proportion H0: p = 0.50, the z test statistic equals 1.05. Use 3 decimal places. (a) What is the p-valu
sergiy2304 [10]

Answer:

(a) The <em>p</em>-value of the test statistic is 0.147.

(b) The <em>p</em>-value of the test statistic is 0.294.

(c) The <em>p</em>-value of the test statistic is 0.8531.

(d) None of the <em>p</em>-values give strong evidence against the null hypothesis.

Step-by-step explanation:

The <em>p</em>-value is well defined as the probability,[under the null hypothesis (H₀)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

We reject a hypothesis if the p-value of a statistic is lower than the level of significance <em>α</em>.

The null hypothesis for the test of population proportion is defined as:

<em>H₀</em>: <em>p</em> = 0.50

The value of <em>z</em>-test statistic is,

<em>z</em> = 1.05

(a)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> > 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value=P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.147.

(b)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> ≠ 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value=2\times P(Z>1.05)\\=2\times 0.1469\\=0.2938\\\approx 0.294

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.294.

(c)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> < 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value= P(Z1.05)=1- 0.1469\\=0.8531

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.8531.

(d)

The decision rule of the test is:

If the <em>p</em>-value of the test is less than the significance level <em>α</em>, then the null hypothesis is rejected at <em>α</em>% level of significance.

And if the <em>p</em>-value of the test is more than the significance level <em>α</em>, then the null hypothesis is failed to be rejected.

The most commonly used level of significance are:

<em>α</em> = 0.01, 0.05 and 0.10

The <em>p</em>-value for all the three alternate hypothesis are:

<em>p-</em>values = 0.147, 0.294 and 0.8531.

All the <em>p</em>-values are quite large compared to the <em>α</em> values.

Thus, none of the <em>p</em>-values give strong evidence against the null hypothesis.

The null hypothesis was failed to be rejected.

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3 years ago
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Answer:

\triangle BOT \cong \triangle IEW

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\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW

We have to prove:

\triangle BOT \cong \triangle IEW

Proof:

\text{In }\triangle BOT \text{ and } \triangle IEW

we can write:

\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}

Hence, the two triangle are congruent by SAS congruency rule.

\triangle BOT \cong \triangle IEW

The attached image shows the two triangle.

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Explanation:
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