The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime 
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+
=-2+2(x+4)/1!-24/16 /2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 /2!+...........
Learn more about taylor series at brainly.com/question/23334489
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Answer:
Once
Step-by-step explanation:
8 can only go into 9 once, if you were to do it a second time, there would be a remainder of 7.
Since we know there are π radians in 180°, then how many radians are there in 153°?
Answer:
(224)10 = (E0)16
I dont know why it wouldnt be right this is the answer...Im acually confused now
Step-by-step explanation:
(224)10 = (E0)16
Step by step solution
Step 1: Divide (224)10 successively by 16 until the quotient is 0:
224/16 = 14, remainder is 0
14/16 = 0, remainder is 14
Step 2: Read from the bottom (MSB) to top (LSB) as E0. This is the hexadecimal equivalent of decimal number 224
Hello,
It is not the same function.
arctan (tan(x))=x
1/tan(x) * tan(x)=1
in the file jointed,
arctan x is in blue
1/tan x in red.
