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NNADVOKAT [17]
3 years ago
7

PLEASE HELP ME WORH THIS

Mathematics
2 answers:
Bad White [126]3 years ago
7 0
Answer: C

Explanation:
Bas_tet [7]3 years ago
5 0

Answer: It’s C

Step-by-step explanation: 5-12-2=-9 and then the 11 stays

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Math I NEED HELP LOOK AT THE IMAGE ALGEBRA IS KILLING ME
HACTEHA [7]

Answer:

4.8

Step-by-step explanation:

1% of 40 is 0.4.

So, just multiply 0.4 by 12 to get 4.8

4 0
3 years ago
Read 2 more answers
A laundry mat can clean five shirts in 20 minutes. What is the rate of shirts per hour?
Anna11 [10]

Answer:

15 shirts in one hour

Step-by-step explanation:

there are 60 minutes in an hour, 20 times 3 is 60, 5 times 3 is 15

5 0
3 years ago
If $x$ is the average of $13$, $-16$, and $6$ and if $y$ is the cube root of $8$, find $x^2 + y^3$. Please Help
Alekssandra [29.7K]

Answer:

If we have a set of N elements:

{x₁, x₂, ..., xₙ}

The mean value (also called the average value) Is calculated as:

Average = (x₁ + x₂ + ... + xₙ)/n

So if x is the average of 13, -16 and 6 ( a total of 3 values)

x will be equal to:

x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1

x = 1

And we know that:

y = ∛8

Remember that:

2*2 = 4

and

4*2 = 8

then

2*2*2 = 2^3 = 8

then ∛8 = 2.

So we have:

y = ∛8 = 2

Now we can replace these values in the equation:

x^2 + y^3

replacing:

x = 1

y = 2

we get:

1^2 + 2^3 = 1 + 8 = 9

5 0
3 years ago
21 The graph of an exponential function is shown on the grid.
morpeh [17]

Answer:

  • C The range is the set of all real numbers greater than 0.

Step-by-step explanation:

We see that the function has positive range and no restriction of domain.

A The range is the set of all real numbers less than 0.

  • Incorrect, positive values only

B The domain is the set of all real numbers greater than-4.

  • Incorrect, the domain can get any value

C The range is the set of all real numbers greater than 0.

  • Correct, the range is restricted to positive values

D The domain is the set of all real numbers less than-4.

  • Incorrect, no restrictions
5 0
3 years ago
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
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