A=p (1+r/k)^kt
A=500×(1+0.02÷3)^(3×4)
A=541.50
Let AM be the distance between point A and the right wall and AN be the distance between A and the left wall.
Δ AMB is an isosceles right triangle and Δ ANC is half of an equilateral triangle.
Length of AM = 30 m. Length of AN = 1/2 · 80 = 40 m.
The distance between the walls is:
30 m + 40 m = 70 m.
Click on the second choice, the 3x one
Answer:
I think its b
Step-by-step explanation:
A=2πrh+2πr2=2·π·5·12+2·π·52≈534
