D)One solution. b=5
Distribute 2 times b plus 2 times 3
2b+6
2b+6+2b=26
Combine like terms 4b+6=26
Subtract 6 from both sides
4b=20
Divide both sides by 4
b=5
Check by substituting 5 for b
2 (5+3)+2(5)=26
2(8) + 2(5)=26
16+10=26
26=26
Answer:
StartFraction StartRoot 3 EndRoot Over 3 EndFraction
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
we know that
In the right triangle XYZ
---> adjacent side divided by the hypotenuse
substitute the values
Remember that
so
substitute
step 2
--> opposite side divided by the hypotenuse
substitute the values
Remember that
so
step 3
--> opposite side divided by adjacent side
substitute the values
Simplify
so
StartFraction StartRoot 3 EndRoot Over 3 EndFraction
x = -2, x = 5
=> f(x) = a(x+2)(x-5), a ∈ R
6/54 times because there are 9 marbles and the orange marble is 1 out of those 9 marbles. If you multiply 6*9= 54 then you notice there is a 6/54 chance of picking any 1 marble out of the 54 times that you decide to pick marbles.
My answer is a and c becuase they equal the same on each side
