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dexar [7]
3 years ago
12

Tell which is greater: 11/15 or 74%

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

The answer is 11/15 < 74%

~hope this is correct, if not I'm sorry~

Step-by-step explanation:

Anettt [7]3 years ago
5 0

Answer:

74% is greater than 11/15

Step-by-step explanation:

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There are 48 people in gym class
nika2105 [10]

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2

Step-by-step explanation:

5/8 8 people in all, 5 were in spin class, 1 was lifting weights, 2 were running.

6 0
3 years ago
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What is greater ? 0.68 or 17/25?​
Alchen [17]

Answer:

these are equal

Step-by-step explanation:

17/25 = 68 / 100 = 0.68

3 0
3 years ago
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Need help with math pls help me will mark brainiest.
saw5 [17]

Answer:

The slope is \frac{-1}{3}.

Step-by-step explanation:

Math Vocabulary            Values

Vertical Change                 -1

Horizontal Change             3

Slope                                   \frac{-1}{3}

8 0
3 years ago
Angle 3 and Angle 6 are alternate interior angles. If angle 3 is (3x-5) degrees and angle 6 is (5x-25), what is the value of x?
Nataly [62]

Answer:

  • x = 10

Step-by-step explanation:

<u>Alternate interior angles measure same as per their property:</u>

  • m∠3 = m∠6
  • 3x - 5 = 5x - 25
  • 5x - 3x = 25 - 5
  • 2x = 20
  • x = 10
3 0
3 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
4 years ago
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