Answer:
Let's simplify step-by-step.
3e−6e+3e−4e
=3e+−6e+3e+−4e
Combine Like Terms:
=3e+−6e+3e+−4e
=(3e+−6e+3e+−4e)
=−4e
Step-by-step explanation:
You are welcome
Answer:
z = x^3 +1
Step-by-step explanation:
Noting the squared term, it makes sense to substitute for that term:
z = x^3 +1
gives ...
16z^2 -22z -3 = 0 . . . . the quadratic you want
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<em>Solutions derived from that substitution</em>
Factoring gives ...
16z^2 -24z +2z -3 = 0
8z(2z -3) +1(2z -3) = 0
(8z +1)(2z -3) = 0
z = -1/8 or 3/2
Then we can find x:
x^3 +1 = -1/8
x^3 = -9/8 . . . . . subtract 1
x = (-1/2)∛9 . . . . . one of the real solutions
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x^3 +1 = 3/2
x^3 = 1/2 = 4/8 . . . . . . subtract 1
x = (1/2)∛4 . . . . . . the other real solution
The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.
(C) cause 17•3=51+39= 90 and that’s a 90 degree
2+2 = 4
4+4 =8
8+8 = 16
16+16 = 32
32+32 = 64
and so on :)
Step-by-step explanation:
Given that,
Two equations,
3x + 11 = 11 .....(1)
And
3(x - 3) = 45
or
3x-9=45 ....(2)
Subtract 11 on both sides of equation (1).
3x + 11-11 = 11-11
3x=0
x = 0
Add 9 to both sides of equation (2)
3x-9+9=45+9
3x = 54
x = 18
Hence, the solution of equation (1) is x=0 and form equation (2) x = 18.
