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vlada-n [284]
3 years ago
10

The height of Liliana's picture frame is 18 inches. The frame and blue matting take up 4.5 inches of the height. Liliana wants t

o know the height of a picture that will fit in the remaining height of the frame. Which equation and solution can be used to solve this problem?
Mathematics
2 answers:
monitta3 years ago
7 0
<span>p+4.5=18 Subtract 4.5 from both sides. The answer is 13.5 inches.</span>
podryga [215]3 years ago
5 0

The answer is C, I took the test.

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I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
A tepee is designed to have a diameter of 10 ft and a volume of 393 ft. At
Citrus2011 [14]

Answer:

15 ft.

Step-by-step explanation:

The tepee is a cone and its volume

= 1/3 pi r^2 h   where r = radius and h = height.

The radius r = 1/2 * 10 = 5 ft.

So we have the equation:

393 = 1/3*3.14* 5^2 * h

h = 393 / (1/3*3.14*25)

=  15.02 ft.

7 0
3 years ago
H Quarshie
Yuki888 [10]

Answer:

28

Step-by-step explanation:

f(6) = -3 * 6 + 10 = -18 + 10 = -8

g(f(6)) = g(-8)

g(-8) = (-8)^{2} + 3 * (-8) - 12 = 64 - 24 - 12 = 64 - 36 = 28

6 0
3 years ago
I am timed here! Please help! Answer only if you know the question. Else please don't.
Anarel [89]

Answer: 3

Step-by-step explanation: [ 3.6 ] represents the greatest integer function [ x ]

If x is an integer use that integer

If x is not an integer use the next smaller integer

[ 3.6 ] is not an integer, hence

[ 3.6 ] = 3

7 0
2 years ago
which of the statements about the following quadratic equation is true? 6x2 - 8 = 4x2 7x the discriminant is greater than zero,
d1i1m1o1n [39]
6x^2 - 8 = 4x^2 + 7x
6x^2 - 4x^2 - 7x - 8 = 0
2x^2 - 7x - 8 = 0
discriminant = b^2 - 4ac; where a = 2, b = -7 and c = -8
d = (-7)^2 - 4(2)(-8)
d = 49 + 64
d = 113

the discriminant is greater than zero, so there are two real roots


5 0
3 years ago
Read 2 more answers
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