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3 years ago

9

Jordon works for a landscaping company during his summer vacation. He is paid $12 per hour for mowing lawns and $14 per hour for

planting gardens. He can work a maximum of 40 hours per week. If m represents the number of hours mowing lawns and g represents the number of hours planting gardens what is 2 systems of inequalities that could be used to represent this situation?

1 answer:

raketka [301]3 years ago

8 0

M+g≤40
12m+14g=x where x is his total earnings for the week
12m+12g+2g=x, so x-2g=12(m+g) and x-2g≤480. Or x≤480+2g. His earnings cannot exceed 480+2g.

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Harper has $14 in her piggy bank. Her mom pays her $12 for chores. How much does Harper now have in the piggy bank?

vovikov84 [41]

Answer:

26

Step-by-step explanation:

14+12=26

1+1=2

4+2=6

7 0

2 years ago

Read 2 more answers

Solve the inequality

GenaCL600 [577]

-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
==============================
32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
============================
6y + 1 > = 10
6y > = 10 - 1
6y > = 9
y > = 9/6 which reduces to 3/2 or 1 1/2

-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
y < = -18/3 which reduces to - 6

so y > = 9/6(or 1 1/2) or y < = -6

3 0

2 years ago

45% of the population of a city are men

leonid [27]

Answer:

$\boxed{\textsf{ The number of children is \textbf{24150}.}}$

Step-by-step explanation:

Given that the 45% of the population of a city are men and 15% are children . The number of women is 64,400 . And we need to find the number of children . Here ,

$\sf\implies Percentage_{(men)}= 45/% .\\\\\sf\implies Percentage_{(children)}= 15\% .$

So the percentage of women will be equal to [ 100 - ( 45 -15) ]% = [ 100 - 60 ]% = 40% .

So let us take the total number of people be x . So ,

$\purple{\bigstar}\underline{\underline{\boldsymbol{ According\ to \ Question :- }}}$

$\sf\implies 40\% \ of \ x \ = \ 64,400 \\\\\sf\implies \dfrac{40x}{100}= 64,400 \\\\\sf\implies x =\dfrac{64,400\times 100}{40}\\\\\sf\implies \boxed{\pink{\sf x = 161,000 }}$

$\rule{200}2$

<u>The </u><u>percentage</u><u> of</u><u> </u><u>children </u><u>=</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>:</u><u>-</u>

$\sf\implies Number_{(children)}= 15\% \ of 161,000\\\\\sf\implies Number_{(children)}= \dfrac{15}{100}\times 161,000 \\\\\sf\implies \boxed{\pink{\frak {Number_{(children)}= 24150 }}}$

5 0

2 years ago

2/9 divided by 5/6<br>help pleaseee

igomit [66]

Hey there!

$\mathsf{\dfrac{2}{9}\div\dfrac{5}{6}}$

$\mathsf{= \dfrac{2\times6}{9\times5}}$

$\mathsf{2\times 6 = \bf 12}$

$\mathsf{9\times5 = \bf 45}$

$\boxed{\mathsf{=\bf \dfrac{12}{45}}}$

$\large\textsf{BOTH NUMBERS has the Greatest Common Factor (GCF) of 3}$

$\mathsf{= \dfrac{12\div3}{45\div3}}$

$\mathsf{12\div3=\bf 4}$

$\mathsf{45\div3=\bf 15}$

$\boxed{\mathsf{=\bf \dfrac{4}{15}}}$

$\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{4}{15}}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\~\frak{Amphitrite1040:)}}$

4 0

2 years ago

Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam

kompoz [17]

For this case, we perform the conversions:

First roll:

$1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x$

$x = \frac {3 * 100} {1}\\x = 300 \ meters.$

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

$c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71$

You can pack 71 boxes.

Second roll:

$1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.$

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

$c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16$

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

$c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11$

You can pack 11 boxes.

Thus, in total you can pack $11 + 16 + 71 = 98 \ boxes$

Answer:

98 boxes

4 0

2 years ago