Question

Two vertical buildings 57 meters apart are 158 meters and 237 meters high. Find the angle of elevation from the top of the shorter building to the top of the taller building, correct to two decimal places.

Answer 1

Given :

Two vertical buildings 57 meters apart are 158 meters and 237 meters high.

To Find :

The angle of elevation from the top of the shorter building to the top of the taller building.

Solution :

Distance between height of building, h = 237 - 158 = 79 m.

Distance between these building , d = 57 m.

Now,

$tan\ \theta = \dfrac{h}{d}\\\\tan\ \theta = \dfrac{79}{57}\\\\tan\ \theta = 1.386\\\\\theta = tan ^{-1} 1.386\\\\\theta = 54.19^{\circ}$

Therefore, the angle of elevation from the top of the shorter building to the top of the taller building is 54.19°.

Hence, this is the required solution.