Hello,
(2x²+7x-3)/(2x+5)=(2x²+5x+2x-3)/(2x+5)
=x(2x+5)/(2x+5)+ (2x+5-5-3)/(2x+5)
=(x+1)/(2x+5)-8/(2x+5)
==> 2x²+7x-3=(x+1)(2x+5)-8
Quotient=x+1
remainder=-8
Answer:
Step-by-step explanation:
f(x) = -5x + 5
g(x) = 8 + 2x
a) (f + g)(x) = f(x) + g(x)
= (- 5x + 5) + ( 8 + 2x )
= - 5x + 2x + 5 + 8
= - 3x + 13
b) (f - g)(x) = f(x) - g(x)
= ( -5x + 5 ) - ( 8 + 2x)
= - 5x + 5 - 8 - 2x
= - 7x - 3
c) (f + g)( 4 )
(f + g)( x ) = - 3x + 13
(f + g) ( 4 ) = - 3 ( 4 ) + 13
= - 12 + 13
= 1
d)(f - g)(- 3)
(f - g) ( x ) = - 7x - 3
(f - g) ( - 3 ) = - 7 ( - 3 ) - 3
= 21 - 3
= 18
Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y =
y = 1500 -
Now area of the rectangle A = xy square feet
A = x[]
For maximum area
A' = = 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 -
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000