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choli [55]
3 years ago
6

In the rectagular prism shown below, GH is parallel to EF. If the equation of GH is 6y-x=2, could the equation of EF be 4=y-1/6x

? Explain your reasoning.
Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Given

GH:

-6y - x = 2

Required

Can EF be

4 = y - \frac{1}{6}x

First, we determine the slope of GH

-6y - x = 2

Solve for 6y

6y = -x - 2

Solve for y

y = -\frac{1}{6}x - \frac{2}{6}

y = -\frac{1}{6}x - \frac{1}{3}

An equation has the form:

y =mx + b

Where

m = slope

By comparison:

m = -\frac{1}{6}

Next, determine the slope of EF

4 = y - \frac{1}{6}x

Make y the subject

y = -\frac{1}{6}x + 4

The slope is:

m = -\frac{1}{6}

Compare the slopes of both lines.

m=m = -\frac{1}{6}

Since they have the same slopes, then the equation of EF is possible

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At midnight, the temperature was -8oF. At noon, the temperature was 23oF. Which expression represents the increase in temperatur
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Answer:

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2 years ago
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dimaraw [331]

Answer: See below

Step-by-step explanation:

27.  -(a-3)

28.  (b-1)(b+3)

29.  (c+4)(c+5)

30.  d(d+5)

31.  -(3/4)(2e-5)

Sorry - I don't have time to enter the details.  Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.

For example:  In problem 30:

(5d-20)/(d^2+d-20) * [??]/20d = 1/4

Factor:  

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ehidna [41]
Given: 

Height of Mountain A = 5210 feet
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Angle of depression:
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Observe that there are two right triangles formed:

From the triangle formed by the helicopter and Mountain B, 

let x = total height of mountain B
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From the second triangle formed by mountain b and a,

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solve for h and y

then, solve for the height of Mountain B:

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