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choli [55]
3 years ago
6

In the rectagular prism shown below, GH is parallel to EF. If the equation of GH is 6y-x=2, could the equation of EF be 4=y-1/6x

? Explain your reasoning.
Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Given

GH:

-6y - x = 2

Required

Can EF be

4 = y - \frac{1}{6}x

First, we determine the slope of GH

-6y - x = 2

Solve for 6y

6y = -x - 2

Solve for y

y = -\frac{1}{6}x - \frac{2}{6}

y = -\frac{1}{6}x - \frac{1}{3}

An equation has the form:

y =mx + b

Where

m = slope

By comparison:

m = -\frac{1}{6}

Next, determine the slope of EF

4 = y - \frac{1}{6}x

Make y the subject

y = -\frac{1}{6}x + 4

The slope is:

m = -\frac{1}{6}

Compare the slopes of both lines.

m=m = -\frac{1}{6}

Since they have the same slopes, then the equation of EF is possible

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