II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Answer:92.4
Step-by-step explanation:
4x+7x=132
10x=132
x=132/10
x=13.2
4x=4×13.2
=52.8
5x=7×13.2
=92.4
There are only 6 place values in 128,955.
If you would round it it could be:
130,000
129,000
128,960
Answer:
1/42
Step-by-step explanation:
1/7 ÷ 6/1
1 x 1 = 1
------------
7 x 6 = 42
1/42
already simplified to the fullest
hope that helps!