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3 years ago

Help meeee pleaseeeeee thanks

Mathematics

2 answers:

Paha777 [63]3 years ago

5 0

When finding the square root you are just multiplying the number by itself the amount of times it is squared.

vodka [1.7K]3 years ago

3 0

(a) 0
(b) 1
(c)4
(d)9
(e)16
(f)25
(g) 36
(h) 49
(I)64
(j)81
(k)100
(l)121
(m)144
(n)169
(o)196
(p)225

Square roots
Hope this helps :))

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Anyone have any idea? i dont have any idea

ladessa [460]

Answer:

$\tt f(x)=2x^2+20x-10$

let y=f(x)

$\tt y=2x^2+20x-10$

$\tt 2x^2+10x=y+10$

$\tt x^2+10x=\frac{1}{2} y+5$

$\tt x^2+10x+25=\frac{1}{2} y+30$

$\tt (x+5)^2=\frac{1}{2} (y+60)$

$\tt 2(x+5)^2=f(x)+60$

$\boxed{\tt f(x)=2(x+5)^2-60}$

Hope it helps! :)

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2 years ago

Differentiate with respect to x : 2xe^x

Gnom [1K]

$\\ \sf\longmapsto \dfrac{d}{dx}2xe^x$

Apply product rule

$\\ \sf\longmapsto \dfrac{d}{dx}2x(e^x)$

$\\ \sf\longmapsto 2x\dfrac{d}{dx}e^x+e^x\dfrac{d}{dx}2x$

$\\ \sf\longmapsto 2xe^x+2e^x$

$\\ \sf\longmapsto 2e^x(x+1)$

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2 years ago

What is 9847.04 rounded to the nearest hundreth

Ainat [17]

It's already rounded to the nearest hundredth. Hundredth's place is the position of the second digit to the right of to the decimal point.

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3 years ago

Limit xtens to 0 x^2logx^2 what is the ans of interminate forms?

GarryVolchara [31]

Rewrite the limit as

$\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}$

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

$\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}$

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3 years ago

Answerrrrrrr plsssssss

Genrish500 [490]

-8 i think? hope this helps!

6 0

2 years ago