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1 year ago

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Write an equation that is parallel to y=-5/2x-5

1 answer:

NeX [460]1 year ago

6 0

A parallel equation (when graphed) will have the same slope, but a different y-intercept.

As long as you keep y = - $\frac{5}{2}$ x + b, you can input anything for b to solve this question.

Given:

y = - $\frac{5}{2}$ x - 5

Equation of a parallel line:

y = - $\frac{5}{2}$ x + 6, y = - $\frac{5}{2}$ x + 1,356, y = - $\frac{5}{2}$ x - 8, etc

Example answer you can use:

y = - $\frac{5}{2}$ x - 8

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DerKrebs [107]

Answer:

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2 years ago

The mariana trench in the pacific ocean is about 36,201 feet deep. the puerto rico trench n the atlantic ocean is about 27,493 f

sleet_krkn [62]

Do you know how to draw a bar graph?
Or model.
It's not something I can draw on this. But for purposes of helping you find how many feet deeper the Marina to the Puerto Rico trench

36,201 minus 27,493

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3 years ago

Read 2 more answers

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mezya [45]

Given:

The figure of two quadrilaterals.

In $ABCD,AB=18,BC=20,CD=22,AD=24$

In $EFGH,EF=27,FG=30,GH=34, EH=36$

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

$\dfrac{AB}{EF}=\dfrac{18}{27}$

$\dfrac{AB}{EF}=\dfrac{2}{3}$

Similarly,

$\dfrac{BC}{FG}=\dfrac{20}{30}$

$\dfrac{BC}{FG}=\dfrac{2}{3}$

$\dfrac{CD}{GH}=\dfrac{22}{34}$

$\dfrac{CD}{GH}=\dfrac{11}{17}$

And,

$\dfrac{AD}{EH}=\dfrac{24}{36}$

$\dfrac{AD}{EH}=\dfrac{2}{3}$

Clearly, $\dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}$ .

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

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2 years ago

Sam is keeping track of the distances at a long jump competition. The jumper from East side High jumped 7.85 meters. The jumper

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7 0

3 years ago

Read 2 more answers

Susan divides the fraction LaTeX: \frac{5}{8}5 8by LaTeX: \frac{1}{16}1 16. Her friend Robyn divides LaTeX: \frac{5}{8}5 8by LaT

marissa [1.9K]

Given:

Susan divides the fraction $\dfrac{5}{8}$ by $\dfrac{1}{16}$ .

Her friend Robyn divides $\dfrac{5}{8}$ by $\dfrac{1}{32}$ .

To find:

The quotient of Susan and Robyn.

Solution:

Susan divides the fraction $\dfrac{5}{8}$ by $\dfrac{1}{16}$ .

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=\dfrac{5}{8}\times \dfrac{16}{1}$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=\dfrac{80}{8}$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=10$

So, Susan's quotient is 10.

Her friend Robyn divides $\dfrac{5}{8}$ by $\dfrac{1}{32}$ .

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=\dfrac{5}{8}\times \dfrac{32}{1}$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=5\times 4$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=20$

So, Robyn's quotient is 20.

Since 20>10, therefore, Robyn will get greater quotient.

3 0

2 years ago