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2 years ago

7

Which points are solutions to the linear inequality y < 0.5x + 2? Select three options. (–3, –2) (–2, 1) (–1, –2) (–1, 2) (1,

–2)

2 answers:

Fantom [35]2 years ago

5 0

Answer:

A.C.E

Step-by-step explanation:

olga55 [171]2 years ago

3 0

Answer:

1 3 5

Step-by-step explanation:

give me brainliest

You might be interested in

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

2 years ago

Please help me with this I don’t understand

Radda [10]

Decreased by means " -".

11.4 -15.7 = -4.3

Answer A.

7 0

3 years ago

Read 2 more answers

If the points (–2, –1), (–1, 0), (2, 3), and (–3, –2) are joined to form a straight line, at what point does the line intersect

Snowcat [4.5K]

Answer:

0

Step-by-step explanation:

Pick 2 points and use the slope formula

(–1, 0), (2, 3)

Slope =(y2−y1)/(x2−x1)

(3−0)(2−−1)

3/3

1

y=1x

Hope this helps! Plz award Brainliest : )

5 0

2 years ago

Greg made 27 ounces of potato salad to serve to 10 people at a picnic if each serving is the same size how much potato salad wip

kirza4 [7]

Answer:

Each person will get 2.7 ounces of potato salad.

Step-by-step explanation:

We are given that;

Total ounces of potato salad Greg made = 27 ounces

Number of persons to be served = 10 people

Now, we are told that each serving is the same size, thus it means each person will receive same size of potato salad.

Thus,

the amount received by each person = Total ounces of potato salad Greg made/total number of persons to be served.

So,

the amount received by each peron

= 27/10

= 2.7 ounces

Thus,

Each person will get 2.7 ounces of potato salad.

6 0

3 years ago

Can anyone help me solve this

yawa3891 [41]

Answer:

a. $45.54; b. $51.42; c. See below

Step-by-step explanation:

a. 193 min

Service charge = $40.00

1st 100 min @ 0.021 = 2.10

Next 93 min @0.037 = <u> 3.44 </u>

Total = $45.54

b. 317 min

Service charge = $40.00

1st 100 min @ 0.021 = 2.10

2nd 100 min @ 0.037 = 3.70

117 min @ 0.048 = <u> 5.62</u>

Total = $51.42

c. Piecewise function

The charge is

$40.00 + 0.021t if t ≤ 100
$42.10 + 0.037(t - 100) if 100 < t ≤ 200
$45.80 + 0.048 (t - 200) if t > 200

which we can write like this:

$f(t) =\begin{cases}40.00 + 0.021t & t \leq 100\\42.10 + 0.037(t-100) & 100 < t \leq200\\45.80 + 0.048(t-200) & t > 200\end{cases}$

5 0

2 years ago