The equation of this parabola will have the form f(x) = a(x+5)(x-4), which works out to f(x) = a(x^2 + x - 20). Since the parabola passes thru (3,40),
40 = a(3^2 + 3 - 20), or 40 = a(-8), so a = -5.
Thus, the equation of this parabola is y = -5(x^2 + x - 20).
Answer:
Part 1) The ratio of the perimeter of ΔHKO to the perimeter of ΔFGO is 
Part 2) The ratio of the area of ΔKHO to the area of ΔGFO is 
Step-by-step explanation:
Part 1)
we know that
If two figures are similar , then the ratio of its perimeters is equal to the scale factor
In this problem
Triangles HKO and FGO are similar by AAA Theorem
Find the scale factor
The scale factor is equal to the ratio of its corresponding sides

Part 2) Find the ratio of the area of ΔKHO to the area of ΔGFO
Area of ΔKHO

Area of ΔGFO

The ratio of its areas is equal to

Alternative Method
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
In this problem we have that
The scale factor is 
so
squared the scale factor
----> is correct
There are 30 men. the way to check this is my dividing 36/6 and you get 6.
Each book costs $15. 90 divided by 6 is 15 which is also 90 over 6.
Answer:
2.1 < x <2.5
Step-by-step explanation:
i’m taking the test rn i’m not sure if it’s correct i’ll lyk!