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Tcecarenko [31]
3 years ago
5

Sarah went on a run. On her run she found 6 rocks. When she was going back home she found 7 more rocks. When she got home she re

lized she lost 2 of the rocks. How many rocks does she have now?
Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

11

Step-by-step explanation:

first you add 6 + 7 = 13

then you 13 - 2 which gives you eleven!

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A= l x w
5x * 2x^2 - 4x + 13
10x^3 - 20x^2 + 65x
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Nataly [62]

Answer:

B

Step-by-step explanation:

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Please solve this quick.
Ivenika [448]

Should be JK

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6 0
2 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
13
Cerrena [4.2K]

Answer:

<h2>2x-10 = 65-x</h2><h2 />

Step-by-step explanation:

just add up both alternate internal angles as they are both equal

so, the equation is: 2x-10 = 65-x

7 0
3 years ago
Read 2 more answers
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