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Lena [83]
3 years ago
11

Sqrt(y^6) = -y^3 y=?

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

they answer is y^6=−y^3

Step-by-step explanation:

Kipish [7]3 years ago
3 0

Answer:

y^6=−y^3

Step-by-step explanation:

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Help please this is urgent
krek1111 [17]

Answer:

1/8

Step-by-step explanation:

The figure is cut into eighths. 2/16 is equal to 1/8

6 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is a rectangle. If AG = -7j + 7 and DG = 5j + 43, find BD
Kaylis [27]

<em>BD</em> = 56

Step-by-step explanation:

Step 1: In rectangle, the diagonals are congruent and bisect each other.

So, <em>AC</em> = <em>BD</em>

⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>

⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>

⇒ 2<em>AG</em> = 2<em>GD</em>

⇒<em>AG</em> = <em>GD</em>

⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43

⇒–7<em>j</em> – 5<em>j</em> = 43 – 7

⇒–12<em>j</em> = 36

⇒<em>j</em> = –3

Step 2: <em>BD</em> = 2<em>DG</em>

<em>BD</em> = 2(5<em>j</em> + 43)

     = 2(5 (–3) + 43)

     = 2(–15 + 43)

     = 2 × 28

     = 56

Hence, <em>BD</em> = 56.

4 0
3 years ago
Write the equation in the form Ax + By = C. Find an equation of a line passing through the pair of points (-7,3) and (-8,-9).
Illusion [34]

Answer:

  12x -y = -87

Step-by-step explanation:

You can start with the 2-point form of the equation of a line and manipulate it to give you the standard form.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (-9 -3)/(-8 -(-7))(x -(-7)) +3

  y = (-12/-1)(x +7) +3

  y = 12x +84 +3

  -12x +y = 87 . . . . . subtract the x-term

  12x -y = -87 . . . . . . make the leading coefficient positive (per standard form)

3 0
3 years ago
Write the equation....
BaLLatris [955]
1-0/-1-0 = -1
Y- 0 = -(x-0)
Y=-x
Y - 1 = -(x+1)
Y-1= -x-1
Y = -x
5 0
3 years ago
Why is water not used as a solvent in paper chromatography​
Anastaziya [24]

Answer:

Because the kind of compounfds that you try to determine using paper chromatography (organic compounds) are usually not soluble in water. Furthermore, water could react chemically with some of this compounds, because it's a very reactive molecule. You need organic solvents that are mostly inert.

8 0
3 years ago
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