All categories

3 years ago

30.28 kg of beef were placed into 24 packages of equal weight. What is the weight of one package of beef? Please show your work.

Mathematics

1 answer:

klemol [59]3 years ago

5 0

Answer:

1.26kg per package

Step-by-step explanation:

30.28/24= 1.2616...

You might be interested in

How many feet are in 1 yard? i yard is how many feet

Katena32 [7]

There are 3 feet in one yard

3 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL MARK BRAINLIEST

Lelu [443]

Answer:

$27 \: {km}^{2}$

Step-by-step explanation:

Given is the shape of a trapezoid.

Therefore,

Area of the trapezoid

$= \frac{1}{2} (2 + 7) \times 6 \\ \\ = 9 \times 3 \\ \\ = 27 \: {km}^{2}$

5 0

3 years ago

It should take 5.22 minutes to clean a shower. You have 5 showers that need to be cleaned. How many minutes should it take for y

Pavlova-9 [17]

It will take 26.1 minutes because 5.22x5 is equal to 26.1

8 0

3 years ago

Given the cost function C(x) = 0.81x + 60, 420 and the revenue function R(x) = 1.87x, find the break-even point

Viktor [21]

Answer:

x = 57,542.8571

Step-by-step explanation:

C(x) = 0.81x + 60,420

R(x) = 1.87x

At break even point, Cost function and revenue function becomes equal.

-> C(x) = R(x)

-> 0.81x + 60,420 = 1.87x

-> 60420 = 1.87x - 0.82x

-> 60420 = 1.05x

-> x = 60420/1.05

-> x = 57,542.8571

Thus, at break even point x = 57,542.8571

7 0

2 years ago

in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

4 0

3 years ago