All categories

3 years ago

What is 3 1/18 as a decimal

1 answer:

7 0

3 1/18 = 3 + 1/18

= 3/1 + 1/18

= (3/1 * 18/18) + 1/18

= 54/18 + 1/18

= 55/18

= 55 ÷ 18 = 3.055556

OR

3 1/18 = 3 + 1/18

= 3 + (1 ÷ 18)

= 3 + 0.055556 = 3.055556

You might be interested in

5x-3=13-3x(if there is no solution,type in ''no solution'') x= Answer

Sati [7]

Answer:

just solve it and it will come out

8 0

3 years ago

Read 2 more answers

3 over 5 is 30% of what number?

denis23 [38]

3/5 = 0.3 * x
3/5 is 30% of x - This is how they match up from the word problem to a number sentence

So to solve it...
3/5 = 0.3x
x = 3/5 ÷ 0.3 = 2

8 0

3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

Whoever answers gets brainlist!

guajiro [1.7K]

Answer: The Correct Answer is 6 because 16+24 is 40 then minus 10 is 30

16-15 is 1 then plus 4 is 5 then you divide 30 by 5 and get 6

Step-by-step explanation: BRAINLIEST PLS

6 0

3 years ago

Read 2 more answers

6cos(20πt-π)+6√3cos(20πt-π\2)

juin [17]

Answer:

Answer is -6t

Step-by-step explanation:

${ \tt{ = (6 \cos(20\pi t) \cos(\pi) + 6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t) \cos( \frac{\pi}{2} ) + \sin(20\pi t) \sin( \frac{\pi}{2} )) }} \\ = { \tt{ (- 6t + 0) + (0 + 0)}} \\ = { \tt{ - 6t}}$

Note that π is 180°

5 0

2 years ago