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2 years ago

Jane cycled 32km, correct to the nearest km.

Mathematics

1 answer:

o-na [289]2 years ago

4 0

Answer:

31.5

and

32,4

Step-by-step explanation:

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How do you work out percentages

Shkiper50 [21]

You take the decimal of say .48 and pull the it back so it would be 48%

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3 years ago

Read 2 more answers

Find the area of the rhombus

Valentin [98]

Answer:

your answer will be option 2

120 units

Step-by-step explanation:

hope this helps have a nice day/ night !! ^_^

3 0

3 years ago

Evaluate the expression for the given value of the variable. <br> 29 + 5/6r <br> r = -1/2<br> find r

Dmitrij [34]

Hey there!

The solution to your question is

We simply plug the "r" value into the equation and solve:

29 + (5/6)(-1/2)

29 + -5/12

28 7/12

Hope it helps! Have an amazing day, and remember, You've got this!

4 0

2 years ago

Since f is parallel to line g, use the diagram to the right right to answer the following question (I need help with problem D a

Snezhnost [94]

Given,

The line f and g are parallel lines.

a)The measure of angle 2 is 117 degree.

By exterior atlernate angle property,

$\begin{gathered} \angle2=\angle7 \\ \angle7=117^{\circ} \end{gathered}$

The measure of angle 7 is 117 degree.

b)The measure of angle 4 is 68 degree.

By sum of adjacent angle between two parallel lines property,

$\begin{gathered} \angle4+\angle6=180^{\circ} \\ \angle6=180^{\circ}-68^{\circ} \\ \angle6=112^{\circ} \end{gathered}$

The measure of angle 6 is 112 degree.

c)The measure of angle 5 is 32 degree.

By alternate interior angle property,

$\begin{gathered} \angle4=\angle5^{} \\ \angle4=32^{\circ} \end{gathered}$

The measure of angle 4 is 32 degree.

d)The measure of angle 7 is 121 degree.

By corresponding angle property,

$\begin{gathered} \angle7=\angle3^{} \\ \angle3=121^{\circ} \end{gathered}$

The measure of angle 3 is 121 degree.

3 0

1 year ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago