Answer:
It seems like the question is not complete. So, I will asume that the complete question is: " A bomb is to be dropped along a mile-long line that stretches across a practice target. The target center is at the midpoint of the line. The target will be destroyed if the bomb falls within a tenth of a mile on either side of the center. Find the Probability that the target is destroyed if the bomb falls randomly along the line."
Step-by-step explanation:
The total of possible cases is the length of the line = 1 mi ;
The favourable cases are the two lengths of 0.1 mi = 0.2 mi ;
Assuming the bomb has no bias for any point ,
the probability of favourable cases' occurrence is 0.2/1 = 0.2
L = 4 + w
perimeter = 38
38 = w + 4 + w
2w = 34
w = 17
L = 4 + 17
L = 21
i am a mathematics teacher. if anything to ask please pm me
Answer:
Step-by-step explanation:
(x₁, y₁) = (19 , -4) & (x₂ ,y₂) = (17, -20)

![= \frac{-20-[-4]}{17-19}\\\\= \frac{-20+4}{17-19}\\\\= \frac{-16}{-2}\\\\= 8](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-20-%5B-4%5D%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-20%2B4%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-16%7D%7B-2%7D%5C%5C%5C%5C%3D%208)
m = 8
Parallel lines have same slope.
Parallel slope = 8
Slope of perpendicular line = 
Perpendicular slope = 
ANSWER
My answer is in the photo above
Its just 30x60=1800...right?