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stira [4]
3 years ago
9

1.

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

i think 126 different bowls

correct me if im wrong

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A recipe for cookies asks for 2/3cup of sugar for ever 2teaspoons of vanilla. How much sugar was used per teaspoon.
lozanna [386]

Answer:

one and one third, or B

Step-by-step explanation:

you would do 2/3 divided by 2 to find the unit rate. it comes out to be 1.3333....  convert into a fraction and the answer is B.

i hope this helped you, im happy to help!

please mark brainliest?

3 0
3 years ago
From a random sample of 40 people at a dinner party, 15 ordered the steak dinner. If there are a total of 212 people at the dinn
vesna_86 [32]
B maybe or A
Because 15 percent of 212 is 31.8 so it’s closer to 40 maybe
5 0
3 years ago
Help me please please help
Dmitrij [34]

1) 8y + 9         2) 2n + 4        3) 3d + 5h

rearrange the equations and combine like terms. combine the terms with the same variables and add / subtract them.

for example number 1:

9y - 11 + 20 - y

is the same thing as

<em>9y - y</em> <u>+ 20 - 11</u>

and now you can easily combine them:

<em>8y</em> + <u>9</u>

i hope this helps!

4 0
3 years ago
-14(3a+6)=12(6-4a)+12 and steps please
Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

14(3a+6)+12(6-4a)+12=0 (using distributive property)

42a+84+72-48a+12=0 ( adding the like terms )

-6a+168=0

-6a=-168

6a=168

a=\frac{168}{6}

Therefore a=28

Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

8 0
3 years ago
What is log b^b^6x equivalent to (The b is under log and ^b)? How do you know?
Arturiano [62]

Answer: 6x

Work Shown:

For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that \log_b(b) = 1 meaning that the log base of itself is 1

log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above

log(b^(6x)) = 6x*1 .... use the second rule mentioned

log(b^(6x)) = 6x

4 0
3 years ago
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