Given:
The radius of circle is 11 inch
The value for pi is 3
The objective is to find the area of the circle.
The area of the circle is given by the formula:
Substituting ,r = 11
We get:
Hence, the area of the circle is 363 square inches
-3,4 the reflection is just making it positive or negative in a different section in this case u change the y to a positive and put it on the second plain
Hope I helped plz giv brainlyest bro I need it
This problem already gave us the slope and y-intercept, so all that's left to do is plug those two values into slope-intercept form.
Slope-Intercept Form: y = mx + b
---m is the slope
---b is the y-intercept
y = 8/3x + 5
Hope this helps!! :)
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
we have
----> inequality A
The solution of the inequality A is the interval ------> [-1,∞)
-------> inequality B
The solution of the inequality B is the interval ------> (-∞,7]
The solution of the compound inequality is
[-1,∞) ∩ (-∞,7]=[-1,7]
therefore
the answer in the attached figure
