Answer:
CI=P*(1 + R/100)^18
A=(CI + P) = P(1+R/100)^18
13500/P=1(100+R/100)^18
A/P=(100+R/100)^18
A/P=(100+R/100)^18
A=13500$ as (750 * 18)
(13500)/P=(1 +1.15/100)18
(13500)/P=(1+1.15/100)18
13500=((1.0115)^18
P=R$10989.02
Step-by-step explanation:
CI=Compound Interest
A=Amount
P=Principal.
Answer:
Step-by-step explanation:
Hello. Would love to try and help, your screenshot is not showing up when I click on it though.
Answer:
the answer is 2.5 or 2 1/2
hope this helps :)
Answer:
The probability that a student is an undergraduate student, given that the student received a plus grade is 0.92
Step-by-step explanation:
The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:

Denote the events as follows:
<em>X</em> = a students is a graduate
<em>Y </em>= a students is a under-graduate
+ = a student received one or more plus grades
- = a student received one or more minus grades
Consider the tree diagram below.
According to the tree diagram, the probability that a student is an undergraduate student, given that the student received a plus grade is:
P (+ | Y) = 0.92
Thus, the probability that a student is an undergraduate student, given that the student received a plus grade is 0.92.
Answer/Step-by-step explanation:
Part A:
![Key:\left[1 Adult = 4 Student]](https://tex.z-dn.net/?f=Key%3A%5Cleft%5B1%20Adult%20%3D%204%20Student%5D)

<u> 12 Student = 3 Adult</u>
<u>24 Student = 6 Adult</u>
<u>40 Student = 10 Adult</u>
Part B:
33 Student
Hence, divide 33 by 4 = 8 with a remainder of 1.
Therefore, 8 Adult and for the remainder 1 student either one Adult takes 5 Student or Needed 9 Adult.