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Sergio039 [100]
2 years ago
7

PLS HELP.... If 4x^2 + bx + 9 = 0, where b is the constant, has exactly one solution, what is a possible value of b ?

Mathematics
2 answers:
IgorLugansk [536]2 years ago
3 0
You can use the discriminant rule, which is :
b^2 -4ac
“exactly one solution” means that it is equal to zero
so:
b^2 -4(4)(9)=0
b^2 -4(36)=0
b^2 -144=0
b^2=144
square root both sides
b=12 or -12

hope this helps !
Elden [556K]2 years ago
3 0

Answer:

Since the equn is quadratic and has equal roots, it's delta k^2–4*4*9 =0 => k= (+ or -) 2*2*3 = (+ or -) 12

Step-by-step explanation:i hope this is correct im so sorry if not aizawa

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<u>Pre-Algebra</u>

Equality Properties

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