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2 years ago

Find the value of X 7/x-10 = 3/6

Mathematics

2 answers:

DiKsa [7]2 years ago

6 0

Answer:

2/3

Step-by-step explanation:

nikdorinn [45]2 years ago

5 0

Answer:

2/3

Step-by-step explanation:

7/x -10 = 3/6

7/x =3/6 +10

7/x = 63/6

42 = 63x

x = 42/63 or 2/3

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ms green tell you that a right triangle has a hypotenuse of 13 and a leg of 5 . She asks you to find the other leg of the triang

Montano1993 [528]

Answer:

$\large \boxed{12}$

Step-by-step explanation:

We can apply Pythagoras' Theorem.

$\begin{array}{rcc}a^{2} & = & b^{2} + c^{2}\\13^{2}& = & 5^{2} + c^{2}\\169& = & 25 + c^{2}\\c^{2}& = & 144\\c & = & \sqrt{144}\\& = & \mathbf{12}\\\end{array}\\\text{The other leg of the triangle is $\large \boxed{\mathbf{12}}$}$

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2 years ago

If a+b=9 and ab=18,find the value of a and b.

Blizzard [7]

Answer:

Given:

a + b = 9

=> a = 9 - b

Given:

a x b = 18

=> (9 - b) x b = 18

=> 9b - b^2 = 18

=> b^2 - 9b + 18 = 0

=> (b - 3)(b - 6) = 0

=> b = 3 => a = 6

=> b = 6 => a = 3

Hope this helps

3 0

2 years ago

Which quantity is use to generate the error bars on a graph?

rodikova [14]

The error bars are used to indicate the variability of the data presented in a graph.

There are several quantities that can be used to generate error bars in the graph. These are:
standard deviation
standard error
confidence interval

Usually, one standard deviation above and below the mean is used although it is advised to indicate which variability data is used to generate the error bars in the graph since the 3 quantity given are not equal.

7 0

2 years ago

PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!ASAP

AveGali [126]

Answer:

x=2.50

Step-by-step explanation:

But I am not sure if its positive or negative.

6 0

2 years ago

Find the equation of the line that contains the given point and the given slope. Write the equation in slope-intercept form.

stealth61 [152]

The slope-point form of a line:

$y-y_0=m(x-x_0)$

The slope-intercept form of a line:

$y=mx+b$

$m=6,\ (4,\ 1)\to x_0=4,\ y_0=1$

Substitute

$y-1=6(x-4)\qquad|\text{use distributive property}\\\\y-1=6x-24\qquad|\text{add 1 to both sides}\\\\\boxed{y=6x-23}$

$m=-5,\ (6,\ -3)$

Substitute

$y-(-3)=-5(x-6)\qquad|\text{use distributive property}\\\\y+3=-5x+30\qquad|\text{subtract 5 from both sides}\\\\\boxed{y=-5x+24}$

$m=-\dfrac{1}{2},\ (-8,\ 2)\\\\y-2=-\dfrac{1}{2}(x-(-8))\\\\y-2=-\dfrac{1}{2}(x+8)\\\\y-2=-\dfrac{1}{2}x-4\qquad|\text{add 2 to both sides}\\\\\boxed{y=-\dfrac{1}{2}x-2}$

$m=0,\ (-7,\ -1)\\\\y-(-1)=0(x-(-7))\\\\y+1=0\qquad|\text{subtract 1 from both sides}\\\\\boxed{y=-1}$

3 0

2 years ago