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ddd [48]
3 years ago
7

What is the common ratio for this geometric sequence?

Mathematics
2 answers:
juin [17]3 years ago
4 0
Answer is c 3 because it is multiplied 3 everytime
Alexxandr [17]3 years ago
4 0

Answer:

Common ratio for the sequence is 3

Step-by-step explanation:

Given sequence is

5, 15, 45, 135,.....

To find out common ratio, divide the second number by the first number

\frac{15}{5} =3

\frac{45}{15} =3

\frac{135}{45} =3

we got 3 that is our common ratio 3

Common ratio for the sequence is 3

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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
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Answer:

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Step-by-step explanation:

<u>Part A </u>

Price Function= 580 - 10x

The revenue function

R(x)=x\cdot (580-10x)\\R(x)=580x-x^2

The marginal revenue function

\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x

<u>Part B </u>

<u>(Fixed Cost)</u>

The total cost function of the company is given by c=(30+5x)^2

We expand the expression

(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2

Therefore, the fixed cost is 900 .

<u> Marginal Cost Function</u>

If  c=900+300x+25x^2

Marginal Cost Function, \frac{dc}{dx}= (900+300x+25x^2)'=300+50x

<u>Part C </u>

<u>Profit Function </u>

Profit=Revenue -Total cost

580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900

<u> Part D </u>

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

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The number of cakes that maximizes profit is 4.

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