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olchik [2.2K]
3 years ago
12

Perform the indicated operation. 5 2/3 ÷ 2 1/8

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

5 2/3 ÷ 2 1/8 = 17/3 ÷ 17/8 = 17/3 x 8/17 = 8/3 = 2 2/3

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There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e
notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

P_{1}=\frac{7 \ girls}{9 \ students}

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

P_{2}=\frac{6 \ girls}{8 \ students}

Then, the probability of the third girl:

P_{3}=\frac{5 \ girls}{7 \ students}

The fourth girl probability:

P_{3}=\frac{4 \ girls}{6 \ students}

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \  28\%)

Therefore, there's 28% probability that every student in the group is a girl.

5 0
3 years ago
What is the equation for these tables.
marshall27 [118]

Answer:

2

Step-by-step explanation:

The y-intercept is the point on the graph where the line intersects with the y-axis. Since this point must be on the y-axis the x-value must be 0. Every coordinate on the y-axis has an x-value of 0. So, to find the answer find the y-value when x=0. In this case, when x=0, y=2. Therefore, the y-intercept is 2, also written as (0,2).

5 0
3 years ago
Carlota wrote the equation y + 1 = 2 (x - 3) for the line passing through the points (-1, 3) and (2, 9). Explain and correct her
Art [367]

For this case we have the following equation:


y + 1 = 2 (x - 3)

That can be rewritten in the form y = mx + b

Where:


  • m is the slope of the line
  • b is the cut point

So, we have:


y + 1 = 2 (x - 3)\\y + 1 = 2x-6\\y = 2x-6-1\\y = 2x-7

Where:


m = 2 is the slope


b = -7 is the cut point


Carlota has the following points:


(-1, 3) and (2, 9)


To know if the line y = 2x-7 passes through these points, we must replace them in the equation and the equality must be fulfilled. So:


Point (-1, 3):


Substituting:


3 = 2 (-1) -7\\3 = -2-7

3 = -9 It's false, equality is not met. The point (-1, 3) does not go through the line.


The equation written by Carlota is erroneous, the procedure to follow is:


Given(x1, y1) = (- 1, 3) and(x2, y2) = (2, 9), we find the slope:


m=\frac{(y2-y1)}{(x2-x1)}

m=\frac{(9-3)}{(2-(-1))}

m=\frac{6}{3}

m=2

We observe that the slope found by Carlota is the same. Let's see cut point "b". For this we substitute any of the points given in the equation:


y = 2x + b

Substituting (2,9) we have:


9 = 2 (2) + b\\9 = 4 + b\\b = 9-4\\b = 5

Thus, Carlota's error was at the cut-off point. The correct equation of the line that passes through the given points is y = 2x + 5

Answer:


The correct equation of the line that passes through the given points is y = 2x + 5

Carlota's mistake was at the cutoff point


5 0
3 years ago
13. Write an equation for the given function given the amplitude, period, phase shift, and vertical shift.
Paul [167]

Answer:

y=4sin(\frac{2\pi(t+\frac{4}{3}\pi ) }{4\pi } )-2

Step-by-step explanation:

Let's start with the original function.

y=a sin\frac{2\pi t}{T}

We can immediately fill in the amplitude 'a' and period 'T' , as the question defines these for us, and provides values for 'a' and 'T', 4 and 4\pi respectively.

y=4sin(\frac{2\pi t}{4\pi } )

Now we only have phase shift and vertical shift to do. Vertical shift is very easy, you can just add it to the end of the right side of the expression. A positive value will shift the graph up, while a negative value will move shift the graph down. We have '-2' as our value for vertical shift, so we can add that on as so:

y=4sin(\frac{2\pit }{4\pi } )-2

Now phase shift the most complicated of the transformations. Basically, it is just movement left or right. A negative phase shift moves the graph right, a positive phase shift moves the graph left (I know, confusing!). Phase shift applies directly to the x variable, or in this case the t variable. To achieve a -4/3 pi phase shift, we need to input +4/3 pi into the function, because of the aforementioned negative positive rule. Here is what the function looks like with the correct phase shift:

y=4sin(\frac{2\pi(t+\frac{4}{3}\pi ) }{4\pi } )-2

This function has vertical shift -2, phase shift -4/3 \pi, amplitude 4, and period 4\pi.

Desmos.com/calculator is a great tool for learning about how various parts of an equation affect the graph of the function, If you want you can input each step of this problem into desmos and watch the graph change to match the criteria.

8 0
3 years ago
Do the ratios 10:9 and 17:15 form a proportion?
KIM [24]

Answer:

Nope! these ratios do not form a proportion

Step-by-step explanation:

if you use a calculator to divide 10/9, you get 1.111 repeating.

if you use a calculator to divide 17/15, you get 1.133 repeating.

<em>since 1.111 does not equal 1.113, </em><em>these ratios are not proportional. </em>

8 0
4 years ago
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