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olchik [2.2K]
2 years ago
12

Perform the indicated operation. 5 2/3 ÷ 2 1/8

Mathematics
1 answer:
bezimeni [28]2 years ago
8 0

5 2/3 ÷ 2 1/8 = 17/3 ÷ 17/8 = 17/3 x 8/17 = 8/3 = 2 2/3

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b. 112.5 miles. 112.5=45•2.5
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Help me please. Find the measures of CAD and DAE
VladimirAG [237]

well, we know the "sum" of both angles is 90°, notice the rectangle in the corner, so we can say that the angles are simply complementary angles, thus

\left( \cfrac{3}{2}x+20 \right)+2x=90\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( \cfrac{3}{2}x+20 + 2x \right)=2(90)} \\\\\\ 3x+40+4x=180\implies 7x+40=180\implies 7x=140\implies x=\cfrac{140}{7} \\\\\\ x = 20~\hfill \stackrel{\measuredangle CAD}{\cfrac{3}{2}20+20\implies 50}\qquad\qquad \stackrel{\measuredangle DAE}{2(20)\implies 40}

8 0
2 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

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3 years ago
0.5 ft<br> 0.4 ft<br> 0.8 ft<br> Area of base =
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Answer:

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