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3 years ago

(-5)^2 divided by 5^4

Mathematics

2 answers:

Pani-rosa [81]3 years ago

4 0

Answer:

Step-by-step explanation:

divide

Nikitich [7]3 years ago

3 0

Answer:

0.04

Step-by-step explanation:

........ i just divided it

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FUNCTION OR NOT /// ALGEBRA I

guapka [62]

Answer:

First figure: The graph is not a function

Second figure:

Statement 1: It is false

Statement 2: It is false

Statement 3: It is right

Step-by-step explanation:

First graph is not a function.

The domain of it is ⇒ 0 ≤ x < 3 , 3 < x ≤ 6 , 6 ≤ x < 9

From the domain ⇒ x = 6 has two corresponding values of y⇒ 3 and 4

∴ It is not a function because every x must have one and only one

corresponding value of y

Second figure

{(3 , 6) , (4 , 6) , (5 , 7) , (6 , 8) , (7 , 10) , (8 , 10)}

Statement 1: It is false because we use x-value to check function or not.

The relation is a function because every x-value has one corresponding

y-value

Statement 2: It is false because 3 ≤ x ≤ 8 means we will use for x all real numbers from 3 to 8 not only the integers 3 , 4 , 5 , 6, ,7 , 8

The domain of this function is { 3 , 4 , 5 , 6 , 7 , 8 }

Statement 3: It is right because the range is the y-value and all the y-value in the function are 6 , 7 , 8 , 10

5 0

3 years ago

A rectangular floor covered without overlaps or gaps by 7 identical tiles, each of the length l and with w. If the w=12 ft, what

SOVA2 [1]

A rectangular floor covered without overlaps or gaps by 7 identical tiles, each of the length l and with w. If the w=12 ft, what is the total area of the floor?

6 0

3 years ago

Hello I need help Finding the probability

Stolb23 [73]

Each petal of the region $R$ is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length $5\sqrt2$ , which implies the segment is subtended by an angle of $\dfrac\pi2$ . This means the area of the segment is

$\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}$
$\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2$

This means the area of one petal is $\dfrac{25\pi}2-25$ , and the area of $R$ is four times this, or $50\pi-100$ .

Meanwhile, the area of $G$ is simply the area of the square minus the area of $R$ , or $10^2-(50\pi-100)=200-50\pi$ .

So

$\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1$
$\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2$
$\mathbb P((X=R)\land(X=G))=0$ (provided these regions are indeed disjoint; it's hard to tell from the picture)
$\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1$