1.67____16.7 Which is bigger

Mathematics

2 answers:

EastWind [94]3 years ago

5 0

Answer:

16.7 would be the bigger

Step-by-step explanation:

Hope this helps :)

Sorry if im wrong :(

bekas [8.4K]3 years ago

4 0

Answer:

16.7 is bigger than 1.67.

Step-by-step explanation:

Numbers have a structure, and a part of that is places. (ex. tens place, one's place, hundreds place, etc.) If you look at the numbers above, only one has a tens place. (Think about it this way; you're comparing 0 to 1 for the tens place. 1 is a larger number, so the number containing 1 in the tens place is larger) Therefore, 16.7 is larger than 1.67

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Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: