That would be c 4x^3-x^2+3x+13
<h2>Hey there! </h2>
<h2>The Reciprocal of 159 is:</h2>


<h2>Hope it help you </h2>
Answer:
y = (x+3)^2 -1
Step-by-step explanation:
The vertex form of the equation is
y = a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-3,-1)
y = a(x- -3)^2 -1
y = a(x+3)^2 -1
Pick another point (-2,0) and substitute it into the equation
0 = a(-2+3)^2 -1 to find a
0 =a(1)^2 -1
0 = a-1
1 = a
y = (x+3)^2 -1
Answer:
X= -13/5
Step-by-step explanation:
i hope this helps :)