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olga2289 [7]
3 years ago
5

Plzzzzzz hellllllllllllpppppppppppp

Mathematics
1 answer:
asambeis [7]3 years ago
3 0

Answer:

1/5

Step-by-step explanation:

The original is 2/10 but simplified it is 1/5

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
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Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c

2000=-\frac{24000}{3}+c

2000=-8000+c

c=10,000

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Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

8 0
3 years ago
The pentagonal prism has a perpendicular distance of 14 units between the bases. The volume of the prism is 840 cubic units. Wha
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Answer:

Option 4. Perimeter = 30 units

Step-by-step explanation:

Since the volume of a pentagonal prism is 840 cubic units.

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Now area of a pentagon

A=\frac{a^{2}}{4}\times\sqrt{5(5+2\sqrt{5})}

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a^{2}=\frac{60}{1.72}=34.90

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You just have to make 36/10 into 3 6/10. After that, it would become 3.6
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-6x because this expression represents the product of a negative number (-6) and a variable (x).
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Does anyone know how to do this ?
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